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nataly862011 [7]
3 years ago
9

How can you use the formula for area of a parallelogram to determine the area of a trapezoid if you forgot the formula for area

of a trapezoid?
Mathematics
1 answer:
son4ous [18]3 years ago
3 0

You can put two identical trapezoids together to form a parallelogram with the same height as the trapezoid and a base length equal to the sum of the base lengths of the trapezoid. The area of the parallelogram is (b1 + b2)h, so the area of the trapezoid is one-half of this area.

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Find the value of x that will make AB<br> А<br> 9x - 40<br> В.<br> 3x + 20<br> x = [?]
Charra [1.4K]

Answer:

x = 10

Step-by-step explanation:

∵ Both angle ∠A and are corresponding angles.

∠A = ∠B

9x - 40 = 3x + 20

9x = 3x + 20 + 40

9x - 3x = 20 + 40

6x = 60

x = 60/6

x = 10

∴ x = [10]

7 0
2 years ago
What is the least common denominator for adding the fractions 4/15, 1/12, and 3/8
il63 [147K]
I think you want the least common multipule (exg LCM of 2,3,4 is 12)

so we find the factors and include all of them so like this

15=3 times 5
12=2 times 2 times 3
8=2 times 2 times 2

so to include all of them we include 3 2's, 1 3 and 1 5 or 2 times 2 times 2 times 3 times 5 or 8 times 15 or 4 times 30 or 120

the LCM is 120

so 4/15=32/120
1/12=10/120
3/8=45/120

add 32/120+10/120+45/120=(32+10+45)/120=87/120
5 0
3 years ago
Read 2 more answers
The graph below shows Sean's distance, d, from his home (in kilometers) as a function of the time, t (in hours).
sdas [7]

Answer:

20

20

5

Step-by-step explanation:

4 0
2 years ago
Please help me asap!!!
fenix001 [56]

Answer:

Already answered it

Step-by-step explanation:

6 0
2 years ago
1)a chord of length 18cm midway the radius of a circle. calculate the radius of the circle correct to 1d.p. 2)if two parallel ch
kykrilka [37]
Part 1:

Given that the length of the chord is 18 cm and the chord is midway the radius of the circle. 

Thus, half the angle formed by the chord at the centre of the circle is given by:

\cos\theta=\frac{\left( \frac{1}{2} r\right)}{r}= \frac{1}{2}  \\  \\ \Rightarrow\theta=\cos^{-1}\left( \frac{1}{2} \right)=60^o

Now, 

\sin60^o= \frac{9}{r}  \\  \\ \Rightarrow r= \frac{9}{\sin60^o} =10.392

Therefore, the radius of the circle is 10.4 cm to 1 d.p.


Part 2I:

Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

\sin\theta= \frac{4}{10} = \frac{2}{5} \\ \\ \theta=\sin^{-1}\left( \frac{2}{5} \right)=23.6^o

Now, 

\cos23.6^o= \frac{x}{10} \\ \\ \Rightarrow x=10\cos23.6^o=9.165\approx9.2cm


Part 2II:

Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

\sin40^o= \frac{y}{10}  \\  \\  \\ \Rightarrow y=10\sin40^o=6.428

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.
3 0
3 years ago
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