Plz help last question on my test
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Answer: The cross will produce 4 offsprings with the following genotypes:
XhXh, XhX, XhY and XY.
Explanation: Hemophilia is an X-linked disease. A woman who carries the hemophilia gene but doesn't not express it is heterozygous, therefore she has a genotype of XhX, and a man who has hemophilia has a genotype of XhY. A cross between them will produce one female and one male who are hemophilic (XhXh and XhY), one female who is a carrier (XhX) and one normal male.
See the punnett square attached for the cross
