Answer:
aₙ = (-3) (-1)ⁿ⁻¹
limit does not exist
Step-by-step explanation:
-3, 3, -3, 3, ...
This is an alternating geometric series where the first term is -3 and the common ratio is -1. The nth term is therefore:
aₙ = (-3) (-1)ⁿ⁻¹
Since the sequence alternates between -3 and 3, the limit as n approaches infinity of aₙ does not exist.
Answer:
When x < 0 (Option 1)
Step-by-step explanation:
The answer to your question would be Option 1, or when x < 0. When you create a table with f(x) and g(x), they're only ever equal when x = 0, which is when f(x) and g(x) both equal 1. When the numbers go into negatives for each equation, f(x) becomes exponentially bigger. Making f(x) > g(x) true when x < 0.
Hope this helps!
Answer:
B im not sure but it seems like the proper answer plz let me know if im right
Step-by-step explanation:
Answer:
Factor x²−6x−27 using the AC method.
(x−9)(x+3)=0
If any individual factor on the left side of the equation is equal to 0 , the entire expression will be equal to 0.
x−9=0
x+3=0
Set x−9
equal to 0 and solve for x.
x=9
Set x+3 equal to 0 and solve for x.
x=−3
The final solution is all the values that make (x−9)(x+3)=0 true.
x=9,−3
Step-by-step explanation:
He’s right For the answer