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mojhsa [17]
2 years ago
6

Solve the inequality. |5 - 2x|> 14

Mathematics
1 answer:
lord [1]2 years ago
8 0

Answer:

x < −9/2

or

x > 19/2

I hope this helps <333

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Which of the following statements correctly illustrate the addition property of equality?
liubo4ka [24]

Answer:

x - y + z = 8

2x +3y -z= -2

3x - 2y -9z = 9

Step-by-step explanation:

[1 - 1  1  8]

[2  3  -1 -2]

[3 -2 -9  9]

4 0
2 years ago
A garden is 4 yards 24 inches wide and 4 yards long. Write the ratio of the width to the length as a fraction in simplistic form
Lana71 [14]

Answer:

7/6

Step-by-step explanation:

The width to length ratio is ...

... width / length = (4 2/3 yards)/(4 yards) = (14/3)/4 = 14/12

... width/length = 7/6

8 0
3 years ago
How do I get from: <br>Sin x = -1/2<br>To: x = 7Pi/6, 11Pi/6
brilliants [131]
A few ways. you can enter it into a calculator for one, but the easiest way would be to reference a unit circle and look for an ordered pair where sin (the y value), is equal to -1/2

on a unit circle, the sin value is -1/2 at 7pi/6 and 11pi/6

because sin is the y value, it will additionally be in the quadrants III or IV based on the fact that (-1/2) as a sin value IS a negative and would have to be found in a quadrant in which sin is negative (the lower half of a coordinate plane, in this case)
8 0
3 years ago
Answering these questions
Rudiy27
1.\\ a)\ y=2x-3\ \ \ |subtract\ y\ from\ both\ sides\\\\\boxed{2x-y-3=0}\\\\b)\ y=\dfrac{1}{3}x-\dfrac{2}{5}\ \ \ |multiply\ both\ sides\ by\ 15\\\\15y=5x-3\cdot2\ \ \ |subtract\ 15y\ from\ both\ sides\\\\\boxed{5x-15y-6=0}


2.\\a)\ 5x-y+3=0\ \ \ |add\ y\ to\ both\ sides\\\\\boxed{y=5x+3}\\\\d)\ 7x+2y-3=0\ \ \ |subtract\ 7x\ from\ both\ sides\\\\2y-3=-7x\ \ \ |add\ 3\ to\ both\ sides\\\\2y=-7x+3\ \ \ \ |divide\ both\ sides\ by\ 2\\\\\boxed{y=-3.5x+1.5}


3.\\y=25x+100\ \ \ \ |subtract\ y\ from\ both\ sides\\\\\boxed{25x-y+100=0}
6 0
3 years ago
If cot theta= 4/3, find csc theta
Marrrta [24]

Answer: Option d.

Step-by-step explanation:

The trigonometric identity needed is:

csc^2\theta=cot^2\theta+1

Knowing that cot\theta=\frac{4}{3}:

Substitute it into csc^2\theta=cot^2\theta+1:

csc^2\theta=(\frac{4}{3})^2+1

Simplify the expression:

csc^2\theta=(\frac{4}{3})^2+1\\\\csc^2\theta=\frac{16}{9}+1\\\\csc^2\theta=\frac{25}{9}

Solve for csc\theta. Apply square root at both sides of the expression:

\sqrt{csc^2\theta}=\±\sqrt{\frac{25}{9}}

csc\theta=\frac{5}{3}

8 0
2 years ago
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