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Anni [7]
2 years ago
6

A diagram shows a kite and its frame.

Mathematics
1 answer:
kati45 [8]2 years ago
7 0

Answer:

indeed it does

Step-by-step explanation:

wheres the diagram exactly?

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Solve for x 3x+3/x-4 = 3x+2/x+4
Lerok [7]

Answer:

here you go! with step by step so you can do it next time

5 0
3 years ago
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Tyler’s brother works in a shoe store.
diamong [38]

Answer:

A)  $22.5

B) $12.6

C) ...

<em>Sorry but i only know two! But i hope this helps you!</em>

8 0
3 years ago
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Please help thank u , you smart ...
Veseljchak [2.6K]

Answer:

6 and 0

Step-by-step explanation:

When we have f(-3) and f(6), that means we plug -3 and 6 in for x to solve for f(x):

f(-3) = (-2/3) * (-3) + 4 = 2 + 4 = 6

f(6) = (-2/3) * 6 + 4 = -4 + 4 = 0

The answers are thus 6 and 0.

5 0
3 years ago
Which of the following polynomials has an even degree and a negative leading coefficient?
spin [16.1K]

Using limits, the polynomial that has an even degree and a negative leading coefficient is:

Polynomial going down from the left and passing through the point negative 7 comma 0 and going to a local minimum and then going up through the point negative 3 comma 0 and 0 comma 8 to a local maximum and then down to the right through the point 4 comma 0.

<h3>What is a limit?</h3>

A limit is given by the value of function f(x) as x tends to a value.

In this problem, to find the polynomial, we have to find the limits as x goes to infinity, hence:

\lim_{x \rightarrow -\infty} f(x) = [tex]\lim_{x \rightarrow -\infty} -a x^n

Since n is even, we have that:

  • \lim_{x \rightarrow -\infty} -a (-\infty)^n = -a \times \infty = -\infty
  • \lim_{x \rightarrow \infty} -a (\infty)^n = -a \times \infty = -\infty

Since it goes down to the left and down to the right, hence the function is:

Polynomial going down from the left and passing through the point negative 7 comma 0 and going to a local minimum and then going up through the point negative 3 comma 0 and 0 comma 8 to a local maximum and then down to the right through the point 4 comma 0.

More can be learned about limits at brainly.com/question/26270080

#SPJ1

4 0
2 years ago
Which statements are true about the interquartile range? Select all that apply. Subtract the lowest and highest values to find t
katen-ka-za [31]

Answer:

The correct options are:

Interquartile ranges are not significantly impacted by outliers.

Lower and upper quartiles are needed to find the interquartile range.

The data values should be listed in order before trying to find the interquartile range.


The option Subtract the lowest and highest values to find the interquartile range is incorrect because the difference between lowest and highest values will give us range.

The option A small interquartile range means the data is spread far away from the median is incorrect because a small interquartile means data is nor spread far away from the median

6 0
3 years ago
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