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borishaifa [10]
3 years ago
10

Suppose you are going to graph the data in the table below. What data should be represented on each axis, and what should the in

crements be? Hours Distance traveled (miles) 1 60 2 35 3 45 4 65 5 55 6 62 7 12 8 65

Mathematics
2 answers:
Brrunno [24]3 years ago
8 0
Distance traveled should be on y axis
hours should be on x axis
increments should be 5
Ugo [173]3 years ago
7 0

Answer:

The data is given in the form of table as :

Hours           Distance traveled in miles

1                        60

2                       35

3                       45

4                        65

5                        55

6                        62

7                         12

8                         65

Since, the values of hours in numerically smaller than than the values of distance traveled in miles so we take the value of hours on x-axis and the distance traveled in miles on y-axis

For, The increment : On the x-axis we take the increment of 5 units and on the y-axis we take the increment of 10 units

And the resultant graph is attached below :

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Two thirds of a number decreased by six is two. what is the number?
Kisachek [45]
Answer:  The number is:  " 12 ". 

____________________________________
  Let "x" represent "the unknown number" (for which we wish to solve.

The expression:

\frac{2}{3} x  <span>− 6  =  2  ;   Solve for "x" ;  
</span>_______________________________________________
Method 1) 

   Add "6" to EACH SIDE of the equation;
_______________________________________________
       →   \frac{2}{3} x  − 6  + 6 =  2 + 6 ;

to get:

      →   \frac{2}{3} x = 8 ;
______________________________________________
Multiply each side of the equation by "\frac{3}{2}" ; to isolate "x" on one side of the equation ; and to solve for "x" ;
______________________________________________
     → \frac{3}{2} * \frac{2}{3} x = 8 * \frac{3}{2} ;

       →  x = 8 * \frac{3}{2} ;

                = \frac{8}{1} * \frac{3}{2} ;

                = \frac{8*3}{1*2} ;
       
                = \frac{24}{2} ;
 
                = <span>1<span>2 .</span></span>
______________________________________________
  x =  12 .
______________________________________________
Method 2)
______________________________________________
\frac{2}{3} x  − 6  =  2  ;   Solve for "x" ; 

   Add "6" to EACH SIDE of the equation;
_______________________________________________
       →   \frac{2}{3} x  − 6  + 6 =  2 + 6 ;

to get:
      →   \frac{2}{3} x = 8 ;
______________________________________________
Multiply each side of the equation by "3" ; to get rid of the "fraction" ;
               → 3 * \frac{2}{3} x = 8 * 3  ;
               → \frac{3}{1} * \frac{2}{3} x = 8 * 3 ;
               → \frac{3*2}{1*3}  x = 8 * 3 
               → \frac{6}{3} x = 24 ; 

                → 2x = 24 ;

 →  Divide each side of the equation by "2" ; to isolate "x" on one side of the equation; & to solve for "x" : 
 
                    2x / 2 = 24 / 2  ;

                        x = 12 .
__________________________________________________
Method 3).
__________________________________________________
\frac{2}{3} x  − 6  =  2  ;   Solve for "x" ;  
_______________________________________________
Add "6" to EACH SIDE of the equation;
_______________________________________________
       →   \frac{2}{3} x  − 6  + 6 =  2 + 6 ;

to get:

      →   \frac{2}{3} x = 8 ;
______________________________________________
Now, divide each side of the equation by " \frac{2}{3} " ;
  to isolate "x" on one side of the equation; & to solve for "x" ;
___________________________________________________
{\frac{2}{3} x }  /  {\frac{2}{3}}  =  8 / {\frac{2}{3}} ;

to get:  x =  8 / {\frac{2}{3}} ;

                =  8 * (\frac{3}{2} ;

                =  \frac{8}{1}  *  \frac{3}{2} ;

                =  \frac{8*3}{1*2} ;

                =  \frac{24}{2} ;

                = 12 ; 
___________________________________________
                         x = 12 .
___________________________________________
NOTE:  Variant:  (in "Methods 2 & 3") :
___________________________________________
At the point where:
___________________________________________
 =  8 * (\frac{3}{2}) ;

  =  \frac{8}{1}  *  \frac{3}{2} ;
__________________________________________
  We can cancel out the "2" to a "1" ; and we can cancel out the "8" to a "4" ;
__________________________________________
  {since: "8÷2 = 4" ; and since:  "2÷2 =1" } ;
__________________________________________
and we can rewrite the expression:
__________________________________________
 \frac{8}{1}  *  \frac{3}{2} ;
__________________________________________
as:   \frac{4}{1}  *  \frac{3}{1} ; 
__________________________________________
which equals:
__________________________________________
→  \frac{4*3}{1*1} ; 

   =   \frac{12}{1} ;

            =  12 .
__________________________________________
         x = 12 . 
__________________________________________
Answer:  The number is:  " 12 ". 
__________________________________________
8 0
4 years ago
Someone help and make sure the answer is right please and thank you!!!! :)
timama [110]

Answer:

A, 6

Step-by-step explanation:

50=8x+2

<em>subtract</em> 2 from both sides

48=8x

<em>divide</em> both sides by 8

x = 6

<em>plz mark me brainliest</em> ;)

3 0
3 years ago
Given h(x) = -x – 4, solve for x when h(x) = 9.
True [87]
X = -5 Hope this helps!
7 0
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The water tank had a maximum capacity of 84 gallons. If the tank was 2/7 full, how many gallons of water did it have
larisa [96]
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Elis [28]
Vocab:
Parallel = same slope
Perpendicular = opposite sign and reciprocal slope

-5/2 opposite and reciprocal = 2/5

Solution: they are perpendicular
4 0
3 years ago
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