All categories

3 years ago

Directions: Post your answer to this question in your Unit 8: Journal 1.

Mathematics

1 answer:

aleksandrvk [35]3 years ago

3 0

Answer:

Tan(∠A) is 4/3.

Step-by-step explanation:

To answer this question, we first need a basic understanding of sin, cos, and tan. The sin of an angle is the opposite over hypotenuse, the cos is adjacent over hypotenuse, and the tan is the opposite over adjancent.

Since sin(∠A) is 4/7, that makes 4 the opposite and 7 the hypotenuse.

Since cos(∠A) is 3/7, that makes 3 the adjacent the 7 the hypotenuse again.

So to get tan(∠A), we just have to put 4/3 since that is the opposite over the adjacent.

You might be interested in

Determine the intercepts of the line. 4x – 1= 3y + 5 x-intercept:(_,_) y-intercept:(_,_)

BARSIC [14]

Answer:

X-intercept: (1.5,0)

y-intercept: (0,-2)

the 1.5 can also be written as 3 over 2 in fraction form.

Hope this helps! :)

4 0

3 years ago

Solve by factoring. p⁴=-25p²

3241004551 [841]

Answer:

p=5i

Step-by-step explanation:

(p^(4)=-25p^(2))/p^(2)

p^(2)=-25

Square root both sides

p=5i

i is the square root of -1, so 5i is five times that much.

The square root of a negative number in not real. That is why it is i, and not a number.

5 0

3 years ago

I need help!!! Can you figure this out?

Aneli [31]

Answer:

128 degrees

Step-by-step explanation:

38+90=128

5 0

3 years ago

the table shows the types of popcorn buckets sold at a concession station for one day. what percent of the buttered popcorn buck

vlada-n [284]

Hi there! The answer is about 23%

First we need to find the total amount of buttered popcorn sold. This is 182 + 140 + 97 = 419 buckets.

To find the percentage of the buttered popcorn buckets that were large, we use the following formula:
$\frac{part}{total} \times 100\%$

Filling in this formula brings us to our answer:
$\frac{97}{419} \times 100\% = 23.15$
Hence, the answer is about 23%

7 0

3 years ago

What is the equation process to this question?

Andreyy89

The given equation is $h(t)=-16t^2+80t+4$ where h is the height, in feet, of a ball and t is the time, in seconds.

Part a: The height of the ball when t = 2 seconds:

The height of the ball above the ground 2 seconds after it is released can be determined by substituting t= 2 in the equation $h(t)=-16t^2+80t+4$ , we get;

$h(2)=-16(2)^2+80(2)+4$

Simplifying the terms, we get;

$h(2)=-64+160+4$

$h(2)=100$

Thus, the height of the ball after 2 seconds is 100 feet.

Part b: The height of the ball when t = 4 seconds:

The height of the ball above the ground 4 seconds after it is released can be determined by substituting t = 4 in the equation $h(t)=-16t^2+80t+4$ , we get;

$h(4)=-16(4)^2+80(4)+4$

Simplifying the terms, we get;

$h(4)=-256+320+4$

$h(4)=68$

Thus, the height of the ball after 4 seconds is 68 feet.

5 0

3 years ago