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choli [55]
3 years ago
5

WHAT IS THE RATE OF CHANGE FOR THIS

Mathematics
1 answer:
stealth61 [152]3 years ago
4 0
Well first find 2 points, I am going to choose (0,0.5) and (1,0.3). So to find rate of change or Slope it is y2-y1/x2-x1 so we are doing that, .3-.5/1-0. which will be -.2/1

Your answer: -.2/1
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Select the correct answer Which pair of statements correctly compares the two data sets? 11 12 9 10 13 6 8 4 5 7 3 0 2 1 : 00 .
ANEK [815]

Answer:

data set 1 : the mean is (1+2+4+4+5+5+6+7+9+9+9+11) / 12 = 72/12 = 6the MAD is :1 - 6 = -5....|-5| = 52 - 6 = -4....|-4| = 44 - 6 = -2...|-2| = 24 - 6 = -2...|-2| = 25 - 6 = -1...|-1| = 15 - 6 = -1...|-1| = 16 - 6 = 0 ...| 0| = 07 - 6 = 1....|1| = 19 - 6 = 3...|3| = 39 - 6 = 3...|3| = 39 - 6 = 3...|3| = 311 - 6 = 5...|5| = 5(5+4+2+2+1+1+0+1+3+3+3+5) / 12 = 30/12 = 2.5 <== the MAD2nd data set :the mean is (1+3+4+6+6+6+7+9+9+10+10+13) / 12 = 84/12 = 7mad is :1 - 7 = -6...| -6| = 63 - 7 = -4...|-4| = 44 - 7 = -3...|-3| = 36 - 7 = -1...|-1| = 16 - 7 = -1..|-1| = 16 - 7 = -1..|-1| = 17 - 7 = 0...|0| = 09 - 7 = 2...|2| = 29 - 7 = 2...|2| = 210 - 7 = 3..|3| = 310 - 7 = 3...|3| = 313 - 7 = 6...|6| = 6(6+4+3+1+1+1+0+2+2+3+3+6) / 12 = 32/12 = 2.67 <== the MADthe difference of the means is 1. This value is less then half of the mean absolute deviation of either data set. <== ur answer

Step-by-step explanation:

4 0
3 years ago
Please help! I attached the question below.
kompoz [17]

Answer:

\frac{2(c+2)}{c(c-2)}

Step-by-step explanation:

\frac{c^{2}-4 }{6c^{4}+15c^{3}}=\frac{(c-2)(c+2)}{c(6c^{3}+15c^{2}) }

Identity used:

a^{2}-b^{2}=(a-b)(a+b)

\frac{c^{2}-4c+4}{12c^{3}+30c^{2}}=\frac{(c-2)^{2}}{2(6c^{3}+15c^{2}) }

Now let us divide the modified expressions:

\frac{(c-2)(c+2)}{c(6c^{3}+15c^{2})} ÷ \frac{(c-2)^2}{2(6c^{3}+15c^{2}) }

we get:

\frac{2(c+2)}{c(c-2)}

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