Pleaseeee helpppp !!!!!!!! Will mark Brianliest correct answer !!!!!!!!!!!!!!!!!!
1 answer:
You might be interested in
Notice that
That is, the <em>n</em>-th term (where <em>n</em> = -1, 0, 1, …, 9) in the sum on the left side has a partial fraction decomposition of
and in the sum, some adjacent terms will cancel and leave you with
Now solve for <em>x</em>, bearing in mind that we cannot have <em>x</em> = 0, -1, -2, …, -10 :
Combine the fractions on the left side:
Then we must have
so that either <em>x</em> = 2 or <em>x</em> = -11.
In the addition problem attached, the letters H = 2, E = 3, A = 9. See the explanation below.
<h3>What is the explanation for the above?</h3>In the problem, A depicts a single digit i.e; A < 9.
=> 4H<10
=>H<3
i.e; H should be 1 or 2.
In units column, 4E should have H in units place in the result. i.e; 1 or 2
As 4E is always an even number, H cannot be 1.
=> H = 2
If H = 2, E can be 3 or 8 for 4E to end in 2.
If E = 8, the result will be a three-digit number => E = 3
So if H = 2 and E = 3
A = 9
Therefore, the letters
H = 2,
E = 3, and
A = 9.
Learn more about addition problems:
brainly.com/question/24530307
#SPJ1
