Can someone please help me answer this question

If the area of a rectangle is 44m squared and the height is 3 2/3m tall what is the base? PLEASE HELP ITS DUE TOMORROW!!!!!

VashaNatasha [74]

Answer:

$x$ = 12

Step-by-step explanation:

area of a rectangle = width x length

Given:

area = 44 m²
width = 3 2/3 m
length = $x$ m

Substitute given values:

area of a rectangle = width x length

⇒ 44 = 3 2/3 x $x$

⇒ $x$ = 44 ÷ 3 2/3

⇒ $x$ = 12

7 0

3 years ago

HELPPPP!!!!!!!! 100 points!!!! I need help on 37-39 thanks!

____ [38]

Answer:

Part 37)

a) Point-slope form $y-5=(1)(x-3)$

b) Slope intercept form $y=x+2$

c) Standard form $x-y=-2$

Part 38)

a) Point-slope form $y-2=0.25(x+4)$

b) Slope intercept form $y=0.25x+3$

c) Standard form $x-4y=-12$

Part 39)

a) Point-slope form $y-3=2(x-1)$

b) Slope intercept form $y=2x+1$

c) Standard form $2x-y=-1$

Step-by-step explanation:

Part 37) Line passing through point (3,5) and slope of 1

Part a) Equation of the line in point slope form

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute the given values

$y-5=(1)(x-3)$

$y-5=(x-3)$ -----> equation of the line in point slope form

Part b) Equation of the line into slope intercept form

The equation of the line into slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-intercept

Substitute the given values in the equation and solve for b

$5=(1)(3)+b$

$5=3+b$

$b=5-3$

$b=2$

substitute

$y=x+2$ -----> equation of the line in slope intercept form

Part c) Equation of the line in standard form

The equation of the line in standard form is equal to

$Ax+By=C$

where

A is a positive integer

B and C are integers

we have

$y=x+2$

Convert to standard form

Subtract y both sides

$y-y=x+2-y$

$0=x+2-y$

Subtract 2 both sides

$-2=x+2-y-2$

$-2=x-y$

Rewrite

$x-y=-2$ ----> equation in standard form

Part 38) Line passing through points (-4,2) and (0,3)

Part a) Equation of the line in point slope form

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

Find the slope m

$m=(3-2)/(0+4)=1/4=0.25$

with the slope m=0.25 and point (-4,2)

substitute the given values

$y-2=0.25(x+4)$ -----> equation of the line in point slope form

Part b) Equation of the line into slope intercept form

The equation of the line into slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-intercept

we have

$m=0.25$

$b=3$ -----> the y-intercept is the point (0,3)

Substitute the given values in the equation

$y=0.25x+3$ -----> equation of the line in slope intercept form

Part c) Equation of the line in standard form

The equation of the line in standard form is equal to

$Ax+By=C$

where

A is a positive integer

B and C are integers

we have

$y=0.25x+3$

Convert to standard form

Multiply by 4 both sides to remove the decimal number

$4y=x+12$

Subtract 4y both sides

$4y-4y=x+12-4y$

$0=x+12-4y$

Subtract 12 both sides

$-12=x+12-4y-12$

$-12=x-4y$

Rewrite

$x-4y=-12$ ----> equation in standard form

Part 39) Line passing through points (1,3) and (2,5)

Part a) Equation of the line in point slope form

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

Find the slope m

$m=(5-3)/(2-1)=2/1=2$

with the slope m=2 and point (1,3)

substitute the given values

$y-3=2(x-1)$ -----> equation of the line in point slope form

Part b) Equation of the line into slope intercept form

The equation of the line into slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-intercept

with the slope m=2 and point (1,3)

Substitute the given values and solve for b

$3=(2)(1)+b$

$3=2+b$

$b=3-2=1$

substitute

$y=2x+1$ -----> equation of the line in slope intercept form

Part c) Equation of the line in standard form

The equation of the line in standard form is equal to

$Ax+By=C$

where

A is a positive integer

B and C are integers

we have

$y=2x+1$

Convert to standard form

Subtract y both sides

$y-y=2x+1-y$

$0=2x+1-y$

Subtract 1 both sides

$-1=2x+1-y-1$

$-1=2x-y$

Rewrite

$2x-y=-1$ ----> equation in standard form

8 0

4 years ago

A kite 100 feet above the ground is being blown away from the person holding its string in a direction parallel to the ground at

VARVARA [1.3K]

Answer:

5√3 ft/s

Step-by-step explanation:

Let h represent the horizontal distance of the kite from the person. Let s represent the string length. Then the Pythagorean theorem tells us ...

s^2 = 100^2 + h^2

2s·ds/dt = 0 + 2h·dh/dt

ds/dt = (h/s)·dh/dt

So, we need to know the horizontal distance when s=200.

200^2 = 100^2 + h^2

40000 -10000 = h^2

h = 100√3

Substituting known values into the equation for ds/dt, we have ...

ds/dt = (100√3)/(200)(10 ft/s) = 5√3 ft/s

The string must be let out at 5√3 ft/s when it is already 200 ft long.

6 0

3 years ago

Billy has 2.4 m of ribbon for crafts. He wants to share it evenly with 12 friends. How many centimeters of ribbon would 7 friend

Dimas [21]

Answer: 34.29cm

Step-by-step explanation:

From the question, we are informed that Billy has 2.4 m of ribbon for crafts and that he wants to share it evenly with 12 friends.

The number of centimeters of ribbon that each of the 7 friends would get will be gotten by dividing 2.4m by 12. We can solve this by first converting 2.4meters to centimeters. This will be:

= 2.4meters = 2.4 × 100cm = 240 centimeters.

We then divide 240cm by 7. This will be:

= 240cm/7

= 34.29cm

5 0

3 years ago

Read 2 more answers

A varies jointly as b and c. Find when b = 7 and c = 9, if the constant is the variation is 3.

bogdanovich [222]

189 would be correct!

7 0

3 years ago

Read 2 more answers