Edwards v. South Carolina is significant because it limited states' ability to

inessss [21]

(repost)

Answer:

B.Energy cannot be destroyed.

Explanation:

In physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time. So, the only possible choice is B.

5 0

3 years ago

Read 2 more answers

True/False. Write out the word "true’’ if the statement is correct. If the statement is false, replace the underlined word(s) wi

Eduardwww [97]

Answer:

A. True

B. True

C. False

D. True

E. True

F. True

G. False

H. True

I. True

J. True

K. False

L. True

M. True

N. True

Explanation: A&B. the quadriceps are a group of muscles connecting through the knees and thighs.

C. Intramuscular injections are usually given in the gluteus maximus because they contain the largest muscle on the buttocks.

G.The semimembranosus is located in the pelvis.

I. Harmstring injuries occur during flexion because it involves bending.

K. Transverse abdominal muscles is the innermost muscles.

6 0

3 years ago

In both photosynthesis and respiration, an electrochemical proton gradient drives chemiosmosis. what establishes the electrochem

just olya [345]

Hydrogen ions. Hydrogen ions are pumped across the membrane during electron transport. They are giving around the membrane by ability of energetic delivery. This establishes an electrochemical ability around the membrane like the single responsible for the action of nerve cells. Nerve cells use Potassium ions.

6 0

3 years ago

In chickens, comb shape is determined by genes at two loci (R, r and P, p). A walnut comb is produced when at least one dominant

Ivenika [448]

Answer and Explanation:

Available data:

Comb shape is determined by genes at two loci (R, r and P, p).

The walnut comb genotype is R_P_.

The rose comb genotype is R_pp.

The pea comb genotype is rrP_.

The single genotype is rrpp.

a. Walnut crossed with single produces 1 walnut, 1 rose, 1 pea, and 1 single offspring:

Parental) RrPp x rrpp

Gametes) RP Rp rP rp rp rp rp rp

Punnet Square) RP Rp rP rp

rp RrPp Rrpp rrPp rrpp

rp RrPp Rrpp rrPp rrpp

F1 phenotype: 25% walnut, 25% rose, 25% pea, and 25% single.

F1 genotype: 4/16 RrPp, 1/16 Rrpp, 4/16 rrPp, 4/16 rrpp.

b. Rose crossed with pea produces 20 walnut offspring.

Parental) RRpp x rrPP

Gametes) Rp Rp Rp Rp rP rP rP rP

Punnet Square) Rp Rp Rp Rp

rP RrPp RrPp RrPp RrPp

F1 phenotype: 100% walnut.

F1 genotype: 16/16 RrPp.

c. Pea crossed with single produces 1 single offspring.

This is not possible, because the pea genotype involves at least one dominant allele P. There are two possible crosses: rrPp x rrpp, which must produce half of the progeny pea and the other half single, or rrPP x rrpp which produce a whole pea progeny with no single offspring.

Parental) rrPp x rrpp

Gametes) rP rp rP rp rp rp rp rp

Punnet Square) rP rp rP rp

rp rrPp rrpp rrPp rrpp

rp rrPp rrpp rrPp rrpp

F1 phenotype: 50% pea, and 50% single.

F1 genotype: 8/16 rrPp, 8/16 rrpp.

d. Rose crossed with pea produces 2 walnut, 1 single, and 1 pea offspring.

This is not possible, because having one of the parents with a rose phenotype involves at least one R allele, which means that there must be rose phenotype in the progeny.

Parental) Rrpp x rrPp

Gametes) Rp Rp rp rp rP rP rp rp

Punnet Square) Rp Rp rp rp

rP RrPp RrPp rrPp rrPp

rP RrPp RrPp rrPp rrPp

rp Rrpp Rrpp rrpp rrpp

rp Rrpp Rrpp rrpp rrpp

F1 phenotype: 25% walnut, 25% rose, 25% pea, and 25% single.

F1 genotype: 4/16 RrPp, 1/16 Rrpp, 4/16 rrPp, 4/16 rrpp.

e. Rose crossed with single produces 31 rose offspring.

Parental) RRpp x rrpp

Gametes) Rp Rp Rp Rp rp rp rp rp

Punnet Square) Rp Rp Rp Rp

rp Rrpp Rrpp Rrpp Rrpp

F1 phenotype: 100% rose (31 individuals equal 100% of the progeny).

F1 genotype: 16/16 Rrpp.

f. Rose crossed with single produces 10 rose and 11 single offspring.

Parental) Rrpp x rrpp

Gametes) Rp Rp rp rp rP rP rp rp

Punnet Square) Rp Rp rp rp

rp Rrpp Rrpp rrpp rrpp

F1 phenotype: 50% rose, 50% single.

F1 genotype: 8/16 Rrpp, 8/16 rrpp.

3 0

3 years ago

The presence of two peripheral efferent neurons in a pathway is typical of the ________ division.

Svetllana [295]

The presence of two peripheral efferent neurons in a pathway is typical of the autonomic division. The autonomic division is part of the vertebrate nervous system and this system is responsible for involuntary action regulation (regulation of the intestines, heart, and glands).

8 0

3 years ago