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Answer:
6. Miles cientos decenas unidades
4 9 5 6
7. Catalina podrá hacer un cuadrado con longitud lateral de 4 cartones
8. 45000000 = 4.5 × 10⁶
0.000000000000056 = 5.6 × 10¹⁴
0.000000000034 = 3.4 × 10¹¹
Step-by-step explanation:
6. Los valores posicionales de dígitos son;
Miles cientos decenas unidades
4 9 5 6
7. El número de cuadrados que tiene Fernando = 12
El número de cuadrados que tiene Catalina = 16
El largo y el ancho de un cuadrado son iguales, por lo tanto tenemos;
largo × ancho = Área del cuadrado
largo = ancho = lado del cuadrado
Lado del cuadrado × Lado del cuadrado = Área del cuadrado
(Lado del cuadrado) ² = Área del cuadrado
Lado del cuadrado = √ (Área del cuadrado)
Para Fernando, Área del cuadrado = 12
Lado del cuadrado para Fernando = √12 = 2 · √3 cartones
Para Catalina, Área del cuadrado = 16
Lado del cuadrado para Catalina = √16 = 4 cartones
Por tanto, Catalina podrá realizar un cuadrado con longitud lateral de 4 cartones
8. 45000000 = 4.5 × 10⁶
0.000000000000056 = 5.6 × 10¹⁴
0.000000000034 = 3.4 × 10¹¹
Answer: 0.0944
Step-by-step explanation:
Given : Sample size of cars : n= 150, sample size is greater than 30 , so we use z-test.
Number of cars tested do have faulty catalytic converters =42
Then the proportion of cars have faulty catalytic converters :
Critical value of z for 99% confidence level :
Formula for Margin of error :
Hence, the required margin of error =
Answer:
(a) P (p' > 0.25) = 0.
(b) P (0.15 < p' < 0.20) = 0.7784.
(c) P (133 < X < 171) = 0.2205
Step-by-step explanation:
Let <em>p</em> = proportion of business trip that were for internal company visit.
It is provided that 19% responded that it was for an internal company visit, i.e.
<em>p</em> = 0.19.
A sample of <em>n</em> = 950 business travelers are randomly selected.
According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:
The standard deviation of this sampling distribution of sample proportion is:
Thus, the distribution of is N (<em>μ</em> = 0.19, <em>σ </em>= 0.013).
(a)
Compute the probability that more than 25% of the business travelers say that the reason for their most recent business trip was an internal company visit as follows:
P (p' > 0.25) = P (Z > 4.62) = 0
*Use a <em>z</em>-table for the probability.
Thus, the probability that more than 25% of the business travelers say that the reason for their most recent business trip was an internal company visit is 0.
(b)
Compute the probability that between 15% and 20% of the business travelers say that the reason for their most recent business trip was an internal company visit as follows:
P (0.15 < p' < 0.20) = P (-3.08 < Z < 0.77)
= P (Z < 0.77) - P (Z < -3.08)
= 0.7794 - 0.0010
= 0.7784
*Use a <em>z</em>-table for the probability.
Thus, the probability that between 15% and 20% of the business travelers say that the reason for their most recent business trip was an internal company visit is 0.7784.
(c)
Compute the proportion of <em>X</em> = 133 and <em>X</em> = 171 as follows:
p' = 133/950 = 0.14
p' = 171/950 = 0.18
Compute the value of P (0.14 < p' < 0.20) as follows:
P (0.14 < p' < 0.18) = P (-3.85< Z < -0.77)
= P (Z < -0.77) - P (Z < -3.85)
= 0.2206- 0.0001
= 0.2205
*Use a <em>z</em>-table for the probability.
Thus, the probability that between 133 and 171 of the business travelers say that the reason for their most recent business trip was an internal company visit is 0.2205.