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omeli [17]
3 years ago
7

Rrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr

Mathematics
2 answers:
Effectus [21]3 years ago
5 0

Answer:

rrrrrrrrrrrrrrrrrrrrrrrrrrr

Step-by-step explanation:

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Marrrta [24]3 years ago
3 0
This is what I got I hope it helps!
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A football is thrown from the top of the stands, 50 feet above the ground at an initial velocity of 62 ft/sec and at an angle of
Anvisha [2.4K]

a. i. The parametric equation for the horizontal movement is x = 43.84t

ii. The parametric equation for the vertical movement is y = 50 + 43.84t

b. the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

<h2>a. Parametric equations</h2>

A parametric equation is an equation that defines a set of quantities a functions of one or more independent variables called parameters.

<h3>i. Parametric equation for the horizontal movement</h3>

The parametric equation for the horizontal movement is x = 43.84t

Since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the horizontal component of the velocity is v' = vcosФ.

So, the horizontal distance the football moves in time, t is x = vcosФt

= vtcosФ

= 62tcos45°

= 62t × 0.7071

= 43.84t

So, the parametric equation for the horizontal movement is x = 43.84t

<h3>ii Parametric equation for the vertical movement</h3>

The parametric equation for the vertical movement is y = 50 + 43.84t

Also, since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the vertical component of the velocity is v" = vsinФ.

Since the football is initially at a height of h = 50 feet, the vertical distance the football moves in time, t relative to the ground is y = 50 + vsinФt

= 50 + vtcosФ

= 50 + 62tsin45°

= 50 + 62t × 0.7071

= 50 + 43.84t

<h3>b. Location of football at maximum height relative to starting point</h3>

The location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Since the football reaches maximum height at t = 1.37 s

The x coordinate of its location at maximum height is gotten by substituting t = 1.37 into x = 48.84t

So, x = 43.84t

x = 43.84 × 1.37

x = 60.0608

x ≅ 60.1 ft

The y coordinate of the football's location at maximum height relative to the ground is y = 50 + 48.84t

The y coordinate of the football's location at maximum height relative to the starting point is y - 50 = 48.84t

So,  y - 50 = 48.84t

y - 50 = 43.84 × 1.37

y - 50 = 60.0608

y - 50 ≅ 60.1 ft

So, the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Learn ore about parametric equations here:

brainly.com/question/8674159

5 0
2 years ago
I need help Please!​
Pachacha [2.7K]

Answer:

36

Step-by-step explanation:

7 0
3 years ago
Joe is performing a dilation. One of his points is Y'(-4, 2), and another point is Y(-2, 1). What scale factor is he using?
IRINA_888 [86]
I would say c.-1/2 but I'm not certain
5 0
4 years ago
Read 2 more answers
Help me plz!!!!!!!!!!!!!
4vir4ik [10]
22 and 27 is the answer. what else do you need??
8 0
3 years ago
111111111111111111111111111111111111111111111111111
Illusion [34]

Answer:

x = 4

Step-by-step explanation:

Step 1: Subtract 4 from both sides.

5x+4−4=24−4

5x=20

Step 2: Divide both sides by 5.

5x

5

=

20

5

x=4

you welcome love

6 0
3 years ago
Read 2 more answers
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