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snow_tiger [21]

3 years ago

10

True or False: The relation {(3, 2), (1, 2), (7, –5), (11, 6), (17, –4), (13, 8)} is a function.

1 answer:

8090 [49]3 years ago

7 0

Answer:

False

Step-by-step explanation:

This is because if you have a function which is Y=2x-4 , then trying to give an example using the given points which (3,2) , here we will have Y=2 upon replacing 3 in the function cause 3 is the value of x and vice versa if we have 2 as the value of Y then x will be 3 . However,if we get the (1,2) the answer for Y will be -2 which is different from the one we have in the question hence this concludes false

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Calculate the measure of angle ADB if angle ACB is 50 degrees.

ahrayia [7]

Answer:

ADB=50°

Step-by-step explanation:

Angles subtended by the same segment are equal

4 0

2 years ago

A car travels 2.83 km in the x-direction, then turns left 65.3 ◦ to the original direction and travels an additional distance of

umka21 [38]

Answer:

4.24 km

Step-by-step explanation:

The x-component of the displacement after the turn is ...

d2·cos(θ) = (3.38 km)cos(65.3°) ≈ 1.41239 km

Adding this to the displacement before the turn, we have ...

x-component of displacement = 2.83 km + 1.41 km = 4.24 km

4 0

3 years ago

Someone help me out please

uysha [10]

1 step (B): raise both sides of the equation to the power of 2.

$(\sqrt{x+3}-\sqrt{2x-1})^2=(-2)^2,\\ (x+3)-2\sqrt{x+3}\cdot \sqrt{2x-1}+(2x-1)=4,\\ 3x+2-2\sqrt{x+3}\cdot \sqrt{2x-1}=4$ .

2 step (A): simplify to obtain the final radical term on one side of the equation.

$-2\sqrt{x+3}\cdot \sqrt{2x-1}=4-3x-2,\\ -2\sqrt{x+3}\cdot \sqrt{2x-1}=2-3x,\\ 2\sqrt{x+3}\cdot \sqrt{2x-1}=3x-2$ .

3 step (F): raise both sides of the equation to the power of 2 again.

$(2\sqrt{x+3}\cdot \sqrt{2x-1})^2=(3x-2)^2,\\ 4(x+3)(2x-1)=(3x-2)^2$ .

4 step (E): simplify to get a quadratic equation.

$4(2x^2-x+6x-3)=(3x)^2-2\cdot 3x\cdot 2+2^2,\\ 8x^2+20x-12=9x^2-12x+4,\\ x^2-32x+16=0$ .

5 step (D): use the quadratic formula to find the values of x.

$D=(-32)^2-4\cdot 16=1024-64=960, \\ \sqrt{D} =8\sqrt{5} ,\\ x_{1,2}=\dfrac{32\pm 8\sqrt{5}}{2} =16\pm 4\sqrt{5}$ .

6 step (C): apply the zero product rule.

$x^2-32x+16=(x-16-4\sqrt{5}) (x-16+4\sqrt{5}) ,\\ (x-16-4\sqrt{5}) (x-16+4\sqrt{5}) =0,\\ x_1=16+4\sqrt{5} ,x_2=16-4\sqrt{5}$ .

Additional 7 step: check these solutions, substituting into the initial equation.

3 0

3 years ago

Solve n + 5(n - 1) = 7

Nina [5.8K]

Answer:

N = 2

Step-by-step explanation:

n + 5(n-1) = 7

n + 5n - 5 = 7

6n - 5 = 7

6n = 12

n = 2

HOPE THIS HELPS

PLZZ MARK BRAINLIEST!!!

7 0

3 years ago

Read 2 more answers

Three cards are drawn with replacement from a standard deck. what is the probability that the first card will be a diamond, the

svlad2 [7]

507/17576 or 0.0288

you take all the probabilities separate then multiply them all together. Then Simplify

6 0

3 years ago