Use the formula: v=v0+at
v is the final velocity
v0 is the initial velocity
a is the acceleration
t is the time
Plug in and solve for t:
0=6+(-2)t
<em>*Subtract 6 from both sides*</em>
-6=-2t
<em>*Divide both sides by -2*</em>
3 seconds=t
Hope this helps!!
D....carbon can also form triple and quadruple bonds
I do beleive that the answer is c
[Ar] 4s1 is the correct answer
B is the correct answer to your question