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Zina [86]
3 years ago
13

An architect designs rectangular flower garden such that the width is exactly 2/3 of the length. of 290 ft of antique picket fen

cing are to be used to enclose the garden find the dimensions of the garden
Mathematics
1 answer:
kramer3 years ago
6 0

Length (L): L

width (w): (2/3)L

Perimeter (P) = 2L + 2w

               290 = 2(L) + 2(2/3)(L)

               870 = 6L + 4L

               870 = 10L

                87 = L

width (w): (2/3)L   = (2/3)(87)   = 2(29)   = 58

Answer: width = 58 ft, length = 87 ft



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Use a graphing utility to graph the function and visually estimate the limits.
levacccp [35]

The value of the \lim_{x \to 0} f(x) and \lim_{x \to \frac{\pi }{3} } f(x) are 0 and 1.153 .

<h3></h3><h3>What is the limiting value of a function?</h3>

Limiting Value of a Function. The function's limit is the value of the function as its independent variable, such as x approaches a certain value called the limiting value. For simple equations, this is similar to finding out the value of y when x has a unique value.

Given that,

f(x) = 4x cos x

First to calculate the limit value of the given function at x=0.

\lim_{x \to 0} f(x) = \lim_{x \to 0} 4x cosx

                   = 4×0×1                              (∵ cos0 = 1)

\lim_{x \to 0} f(x) = 0

Similarly,

\lim_{x \to \frac{\pi }{3} } f(x) = \lim_{x \to \frac{\pi }{3} } 4x cosx

                     =  4×\frac{\pi }{3}×cos\frac{\pi }{3}

                     =  4×\frac{\pi }{3}×\frac{1}{2}                          (∵cos60° = \frac{1}{2})

\lim_{x \to \frac{\pi }{3} } f(x)  = 1.153

Hence, The value of the \lim_{x \to 0} f(x) and \lim_{x \to \frac{\pi }{3} } f(x) are 0 and 1.153.

To learn more about the limit of the function from the given link:

brainly.com/question/23935467

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8 0
1 year ago
A standard deck of cards contains 52 cards. One card is selected from the deck.​(a)Compute the probability of randomly selecting
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a. There are four 5s that can be drawn, and \binom43=4 ways of drawing any three of them. There are \binom{52}3=22,100 ways of drawing any three cards from the deck. So the probability of drawing three 5s is

\dfrac{\binom43}{\binom{52}3}=\dfrac4{22,100}=\dfrac1{5525}\approx0.00018

In case you're asked about the probability of drawing a 3 or a 5 (and NOT three 5s), then there are 8 possible cards (four each of 3 and 5) that interest you, with a probability of \frac8{52}=\frac2{13}\approx0.15 of getting drawn.

b. Similar to the second case considered in part (a), there are now 12 cards of interest with a probability \frac{12}{52}=\frac3{13}\approx0.23 of being drawn.

c. There are four 6s in the deck, and thirteen diamonds, one of which is a 6. That makes 4 + 13 - 1 = 16 cards of interest (subtract 1 because the 6 of diamonds is being double counted by the 4 and 13), hence a probability of \frac{16}{52}=\frac4{13}\approx0.31.

- - -

Note: \binom nk is the binomial coefficient,

\dbinom nk=\dfrac{n!}{k!(n-k)!}={}_nC_k=C(n,k)=n\text{ choose }k

6 0
4 years ago
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yan [13]

Answer:

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Good luck, hope this helped!

5 0
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kolbaska11 [484]

Answer: 7x^2+21x+14

Step-by-step explanation:

(7x+7)(x+2)

Multiply each term in the first parentheses by each term in the second parentheses (FOIL)

7x×x+7x×2+7x+7×2

↘ ↙

7x×x calculate product

7x^2+7x×2+7x+7×2

↘ ↙

7x×2 calculate product

7x^2+14x+7x+7×2

↘↙

7×2 multiply numbers

7x^2+14x+7x+14

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21x collect like terms

7x^2+21x+14 is your end result.

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CaHeK987 [17]

<h3> Answer:</h3><h2>a.215</h2>

I don't know in letter b.

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