While staying in the same period, if we move from left to right across the period, the atomic radius decreases. The reason is, in a period the number of shells remain the same and the number of electrons and protons increase as we move across the period to the right. The increased electrons and protons attract each other with greater force and hence the atomic size decreases.
So the element on the left most will have the largest atomic radius. So the correct ans is Potassium. Potassium will have the largest atomic size among Potassium, Calcium and Scandium.
Answer: 2. Density
3. Physical Property
4. Chemical Change
5. states of matter
Explanation: Density is referred as mass per unit volume. Physical properties are observable characteristics of an object. An new formation of a substance in a chemical reaction is a chemical change. And solids, liquids, and gases are states of matter.
Answer:
Negative Radicals ---→
1).Flouride = F⁻
2). Chloride = Cl⁻
3) Bromide = Br⁻
4) Iodide = I⁻
5) Sulphate = SO₄²⁻
6) Oxide = O²⁻
7) Nitride = N³⁻
8) Sulphur = S²⁻
9) Carbide = C⁴⁻
10) Hydroxide = OH⁻
11) Nitrate = NO₃⁻
12) Carbonate = CO²⁻
13) Hydrogen Carbonate = HCO₃⁻
14) Sulphate = SO₄²⁻
15).Sulphite = SO₃³⁻
16) Nitrate = NO₃⁻
17)Nitrite = NO₂⁻
18) Hydrogen Sulphite = HSO₃⁻
19) Hydrogen Sulphate = HSO₄⁻
20) Chromate = CrO₄²⁻
There are lot of Radicals which cannot be easily written. Although some of the Important Radicals which are commonly used are mentioned above.
Hope it helps,
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Lets name one gas sample as A and other gas sample as B.
we can apply ideal gas law equation for both samples
PV = nRT
P - Pressure of A = Pressure of B
V - volume of A = volume of B
n - number of molecules of both A and B being equal is equivalent to number of moles of A = number of moles of B
R - universal gas constant
Tᵃ - temperature of A
Tᵇ - temperature of B
for gas A
PV = nRTᵃ --1)
for gas B
PV = nRTᵇ ---2)
when we divide both equations
1 = Tᵃ / Tᵇ
Tᵃ = Tᵇ
both temperatures are equal
temperature in Celsius + 273 = temperature in Kelvin
therefore 0 °C = 273 K
the correct answer is
A)
<span>The first gas sample has a temperature of 273 K, and the second gas sample has a temperature of 0 </span>°<span>C</span>
find mass of oxygen by subtracting mass of phosphorus from the total mass
divide the masses by the molar mass to get moles
divide moles by the smallest amount of moles
multiply by 2 to get a nice number
P4O5
