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postnew [5]
3 years ago
14

Benzoic acid, C6H5COOH, melts at 122°C. The density in the liquid state at 130°C is 1.08g/cm3. The density of solid benzoic acid

at 15°C is 1.266g/cm3. In which of these two states is the average distance between molecules greater? If you converted a cubic centimeter of liquid benzoic acid into a solid, would the solid take up more, or less, volume than the original cubic centimeter of liquid?
Chemistry
1 answer:
MaRussiya [10]3 years ago
5 0

Answer:

The correct answer is: Liquid state;  Less volume

Explanation:

Density (ρ) is the physical property of a substance. It is equal to the mass per unit volume of a given substance. The SI unit of density is kg/m³.

Density (ρ) = mass (m) ÷ volume (V)

<u>Given:</u> density of liquid benzoic acid = 1.08 g/cm³ and density of solid benzoic acid = 1.266 g/cm³

As 1.08 g of benzoic acid occupies 1 cm³ volume in the liquid state and 1.266 g of benzoic acid occupies 1 cm³ volume in the solid state.

<u>Thus the molecules of benzoic acid are more densely packed in the solid state as compared to the liquid state</u>.

<u>Therefore, the average distance between the molecules of benzoic acid is greater in the liquid state as compared to the solid state.</u>

<u />

Also, as the benzoic acid in the solid state is more densely packed than benzoic acid in the liquid state.

So, <u>if 1 cm³ of liquid benzoic acid is solidified</u>, then the volume occupied by solid benzoic acid having the same mass, <u>occupies less space or volume as compared to the liquid benzoic acid.</u>

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Answer:

<em>molar mass of the phosphorus chloride = 138.06 g/mol</em>

<em></em>

Explanation:

<em>mass of phosphorus will be the same as mass of CO2, since it is stated that they are of equal amount.</em>

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<em>lets assume that it took the CO2 1 sec to effuse, then the time taken by the phosphorus chloride will be 1.77 sec</em>

From this we can say that

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rate of effusion of the phosphorus chloride = 3.51/1.77 = 1.98 g/s

<em>From graham's equation of effusion</em>,

\frac{Rc}{Rp} = \sqrt{\frac{Mp\\}{Mc} }

Rc = rate of effusion of CO2 = 3.51 g/s

Rp = rate of effusion of phosphorus chloride = 1.98 g/s

Mc = molar mass of CO2 = 44.01 g/mol

Mp = molar mass of the phosphorus chloride = ?

Imputing values into the equation, we have

\frac{3.51}{1.98} = \sqrt{\frac{Mp\\}{44.01} }

1.77 = \frac{\sqrt{Mp} }{6.64}

11.75 = \sqrt{Mp}

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