Answer: The molar solubility of barium fluoride is 0.0183 moles/liter.
Explanation:
The equation for the reaction will be as follows:
By Stoichiometry,
1 mole of gives 2 moles of
and 1 mole of
Thus if solubility of is s moles/liter, solubility of
is s moles/liter and solubility of
is 2s moles/liter
Therefore,
Thus the molar solubility of barium fluoride is 0.0183 moles/liter.
Answer:
252.5g
Explanation:
Given parameters:
Volume of vodka = 0.8L
Molarity of ethanol = 6.86M
Unknown:
Mass of ethanol = ?
Solution:
Molarity is one of the ways of expressing concentration. It is the number of moles of a substance in a solution.
Since Vodka = ethanol + water = solution
Molarity =
Number of moles of ethanol = molarity of vodka x volume of solution
Once we obtain the number of moles, we can derive the mass of the ethanol;
Number of moles = 6.86M x 0.8L = 5.49moles
Mass of ethanol = number of moles x molar mass
molar mass of ethanol = 12 + 3(1) + 12 + 2(1) + 16 + 1 = 46g/mol
Mass of ethanol = 5.49 x 46 = 252.5g