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My name is Ann [436]
4 years ago
13

Describe the ammonium ion, NH4+, and the sulfate ion, SO42-. What compounds would these ions form with potassium and fluoride io

ns
Chemistry
2 answers:
KonstantinChe [14]4 years ago
7 0

Make sure you include these points:

The atoms in each ion are bonded together covalently to form a single unit.

The charge is distributed over the entire ion.

The formula of ammonium fluoride is NH4F.

The formula of potassium sulfate is K2SO4.

frozen [14]4 years ago
6 0
<span>Cations mix with anions, so you know NH4+ won't mix with K+ and SO4(2-) won't miix with F-. For the reason that NH4+ and F- together have single charges, they'll mix in a 1:1 ratio, NH4F. There's two charges on SO4(2-), so it'll need two K+ to mix with, K2SO4.</span>
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This is 20 points!!!
Ann [662]

Answer:

I think it both physical & chemical change :')

5 0
2 years ago
What is the electron configuration for N (nitrogen)?
ollegr [7]

Answer:

1s^22s^22p^3

Explanation:

Nitrogen has the atomic number = 7

So, No. of electrons = 7

<u><em>Electronic Configuration:</em></u>

1s^22s^22p^3

<u>Remember that:</u>

s sub shell holds upto 2 electrons while p sub shell upto 6

7 0
3 years ago
How many liters are in 5.98 moles of nitrogen gas at STP?
Shtirlitz [24]

Answer:

The correct answer is c) 134L

Explanation:

We use the formula PV =nRT. The normal conditions of temperature and pressure are 273K and 1 atm, we use the gas constant = 0, 082 l atm / K mol.

1 atm x   V = 5, 98 mol x 0, 082 l atm / K mol x 273 K

V = 5, 98 mol x 0, 082 l atm / K mol x 273 K / 1 atm

V = 133, 86828 l

8 0
3 years ago
Calculate the standard potential for the following galvanic cell: Fe(s) | Fe2+(aq) || Ag+(aq) | Ag(s) which has the overall bala
Nataly [62]

Answer:

E° = 1.24 V

Explanation:

Let's consider the following galvanic cell: Fe(s) | Fe²⁺(aq) || Ag⁺(aq) | Ag(s)

According to this notation, Fe is in the anode (where oxidation occurs) and Ag is in the cathode (where reduction occurs). The corresponding half-reactions are:

Anode: Fe(s) ⇒ Fe²⁺(aq) + 2 e⁻

Cathode: Ag⁺(aq) + 1 e⁻ ⇒ Ag(s)

The standard cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E° = E°red, cat - E°red, an

E° = 0.80 V - (-0.44 V) = 1.24 V

6 0
3 years ago
How many grams of N2 are in 44.8L at STP?
lutik1710 [3]

Answer: 10 i think

Explanation:

3 0
3 years ago
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