the lenght of the floor is 32 m longer than its width and there is greater than 200 square meters. you will cover the floor comp
letely with tiles. what will be the possible dimension of the floor?
1 answer:
Let’s assume the width of the floor is x and the area is a
To figure out the dimensions we need to figure out the value of the variable (x)
This means that the length is xm+32m (the m is for metres) and that the area is a>200m2
Because it says what is the possible dimensions let make the area 201m2
The formula for the area of a rectangle is length times width so the equation we use to figure out the value of x
201=x+x+32
So let’s collect like terms and solve from there
201=2x+32
201-32=2x+32-32
169=2x
169/2=2x/2
84.5=x
Now that we know the value of x is 84.5 we can figure out the length is 116.5m and the width is 84.5m
Therefore the dimensions of the floor is 116.5m by 84.5m
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If you are adding the fractions themselves it would be 9/17. If the /'s are for division it's 0.53
Answer:
687
Step-by-step explanation:
First, we want to find the area of the rectangle.
The formula is length times width, so it is 27*280, which equals 7560. We divide this by 11 to get 687.27272727.....(repeating)
The answer is 687.
The graph is shown in the attached image.
