Question

the lenght of the floor is 32 m longer than its width and there is greater than 200 square meters. you will cover the floor completely with tiles. what will be the possible dimension of the floor?

Answer 1

Let’s assume the width of the floor is x and the area is a

To figure out the dimensions we need to figure out the value of the variable (x)

This means that the length is xm+32m (the m is for metres) and that the area is a>200m2

Because it says what is the possible dimensions let make the area 201m2

The formula for the area of a rectangle is length times width so the equation we use to figure out the value of x


201=x+x+32

So let’s collect like terms and solve from there
201=2x+32
201-32=2x+32-32
169=2x
169/2=2x/2
84.5=x

Now that we know the value of x is 84.5 we can figure out the length is 116.5m and the width is 84.5m

Therefore the dimensions of the floor is 116.5m by 84.5m