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3 years ago

5

Can any one help? Solve the following equations:

1 answer:

Reika [66]3 years ago

4 0

Answer:

2- x=16/3 or 5.3

4- x=8

Step-by-step explanation:

yeah

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1. Ethan is 48 years old. He is planning on retiring when he turns 62. He has opened an IRA with an

dolphi86 [110]

Whenever he wants? Honestly idk

8 0

3 years ago

Find the 10th and nth term of each G.P.:5,25,125,.....

RUDIKE [14]

Answer:

The $n^{th}$ of the sequence

$t_{n} = ar^{n-1}$

The $10^{th}$ of the sequence

$t_{10} = 5(5)^{10-1} = 9,765,625$

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that the geometric sequence

5, 25 , 125 ,....

First-term a= 5

Difference $r = \frac{25}{5} =5$

The $n^{th}$ of the sequence

$t_{n} = ar^{n-1}$

The $10^{th}$ of the sequence

$t_{10} = 5(5)^{10-1} = 9,765,625$

6 0

3 years ago

the difference between seven times one number and three times a second number is 25. The sum of twice the first and five times t

inysia [295]

$\left \{ {{7*x - 3*y=25} \atop {2*x + 5*y=95}} \right.$

$\left \{ {{7x - 3y=25}(I) \atop {2x + 5y=95}(II)} \right.$

$\left \{ {{7x - 3y=25}simplify*(5) \atop {2x + 5y=95}simplify*(3)} \right.$

$\left \{ {{35x - \diagup\!\!\!\! 15 y=125} \atop {6x + \diagup\!\!\!\! 15y=285}} \right.$

$\left \{ {{35x =125} \atop {6x =285}} \right.$

$41x = 410$

$\boxed{x=10}$

<span>Replace the value of "x" in the second equation (II) to find the value of "y", thus:
</span> $2x + 5y=95$
$2*(10)+5y = 95$
$20+5y=95$
$5y=95-20$
$5y=75$
$y = \frac{75}{5}$
$\boxed{y=15}$

The numbers (10,15)

5 0

3 years ago

Can someone please help me with this question?

Ivan

The answer to you question is yes

5 0

4 years ago

Read 2 more answers

The function is defined by g(x) = 2x^2 + 5<br> Find g(5x)

Anna007 [38]

So, you substitute every x in g(x) for 5x.

2(5x)^2 + 5

10x^2 + 5

5 0

3 years ago