Can any one help?<br><br> Solve the following equations:

Vitek1552 [10]

Answer:

once a plats grew in 2 weeks he was 12 weeks old and he grew by 10 to 60 height lead and and he gained 140 to 155 fat

Step-by-step explanation:

8 0

2 years ago

Find the value of x so that line m is parallel to line l.

MatroZZZ [7]

<h3>Answer: A) 46</h3>

Explanation:

The angles shown are same side interior angles.

For line L to be parallel to line M, the same side interior angles must be supplementary, or they must add to 180.

28+(3x+14) = 180

28+3x+14 = 180

3x+42 = 180

3x = 180-42

3x = 138

x = 138/3

x = 46

4 0

3 years ago

Read 2 more answers

Shona spins a spinner with three equal-sized spaces—red, green, and yellow—and then rolls a six-sided die numbered from 1 to 6.

telo118 [61]

<h2>Answer with explanation:</h2>

<u>Sample size--</u>

It is the collections of all the possible outcomes of an event.

(A)

It is given that:

Shona spins a spinner with three equal-sized spaces—red, green, and yellow and then rolls a six-sided die numbered from 1 to 6.

This means that the possible outcomes are given as follows:

(Red,1) (Green,1) (Yellow,1)

(Red,2) (Green,2) (Yellow,2)

(Red,3) (Green,3) (Yellow,3)

(Red,4) (Green,4) (Yellow,4)

(Red,5) (Green,5) (Yellow,5)

(Red,6) (Green,6) (Yellow,6)

This means that the total number of outcomes are: 18

Hence, the sample size for this compound event is: 18

(B)

If the spinner has four colored spaces.

Let the fourth color be: Blue

Then the possible outcomes are given by:

(Red,1) (Green,1) (Yellow,1) (Blue,1)

(Red,2) (Green,2) (Yellow,2) (Blue,2)

(Red,3) (Green,3) (Yellow,3) (Blue,3)

(Red,4) (Green,4) (Yellow,4) (Blue,4)

(Red,5) (Green,5) (Yellow,5) (Blue,5)

(Red,6) (Green,6) (Yellow,6) (Blue,6)

Hence, the total number of outcomes are: 24

The sample size of this compound event would be 24.

8 0

3 years ago

What are the coordinates of the orthocenter of △JKL with vertices at J(−4, −1) , K(−4, 8) , and L(2, 8) ?

Sati [7]

<u>Answer-</u>

<em>The coordinates of the orthocenter of △JKL is (-4, 8)</em>

<u>Solution-</u>

The orthocenter is the point where all three altitudes of the triangle intersect. An altitude is a line which passes through a vertex of the triangle and is perpendicular to the opposite side.

For a right angle triangle, the vertex at the right angle is the orthocentre of the triangle.

Here we are given the three vertices of the triangle are J(-4,-1), K(-4,8) and L(2,8)

If the triangle JKL satisfies Pythagoras Theorem, then triangle JKL will be a right angle triangle.

Applying distance formula we get,

$JK^2= (-4+4)^2+ (8+1)^2=0+81=81\\\\KL^2= (-4-2)^2+ (8-8)^2=36+0=36\\\\JL^2= (-4-2)^2+(8+1)^2=36+81=117$

As,

$\Rightarrow 117=81+36$

$\Rightarrow JL^2=JK^2+KL^2$

$\Rightarrow \text{JKL is a right angle triangle}$

$\Rightarrow \angle K=90^{\circ}$

Therefore, the vertex at K (-4, 8) is the orthocentre.

3 0

3 years ago

If 27y is a multiple of 9 where y is a digit . What is the minimum value of Y.

stiv31 [10]

<h3>Answer: 0</h3>

Explanation:

The single digits are {0,1,2,3,4,5,6,7,8,9}

So naturally 0 is the first thing to test.

The number 270 is a multiple of 9 because 9*30 = 270. The digits of 270 add to 2+7+0 = 9 showing that it's a multiple of 9. Refer to the "divisibility by 9 rule".

The next possible value of y will be 9 units higher than y = 0, so we go for y = 9. Meaning that 279 is also a multiple of 9 (because 2+7+9 = 18 is a multiple of 9).

4 0

2 years ago

Can any one help? Solve the following equations: