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emmasim [6.3K]
3 years ago
10

Can someone give me the measurements for reflecting this. Gcse foundation Thanks

Mathematics
2 answers:
Elodia [21]3 years ago
4 0

Answer:

( 2 , 1 ) , ( 4 , 1 ) , ( 4 , 4 ) .......

goblinko [34]3 years ago
4 0

Answer:

Points of B are (-4,-1), (-2,-1) and (-4,-4)

Step-by-step explanation:

Points of A are (-4, 1), (-2, 1) and (-4,4)

Name the reflected trangle B.

If you have a point (x,y) and you reflect in the x-axis. That point becomes (x,-y).

Therefore. Points of B are (-4,-1), (-2,-1) and (-4,-4)

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Divide £ 45 among 3 person so that their share are in the ratio 4:5:6
NISA [10]

Answer:

12, 15, 18

Step-by-step explanation:

4x+5x+6x=45

15x=45

x=3

4x=12, 5x=15, 6x= 18

6 0
3 years ago
Round yo the nearest hundred plz it’s not much!!!!!!!!!
natita [175]
A is the answer of not I’m sorry for that
7 0
3 years ago
A triangular playground has sides that are lengths 2x feet, x-1 feet and x feet. If the perimeter of this playground is 27 feet,
Keith_Richards [23]

Answer:

The lengths of the sides of the playground are 14 feet, 6 feet, 7 feet

Step-by-step explanation:

At first, let us find the perimeter of the playground

∵ Perimeter of a triangle is P = S1 + S2 + S3

∵ The sides of the triangular playground are (2x) ft, (x - 1) ft, and x ft

∴ S1 = 2x, S2 = x - 1, S3 = x

→ Substitute them in the rule of the perimeter above

∵ P = 2x + x - 1 + x

→ Add the like terms

∴ P = (2x + x + x) - 1

∴ P = 4x - 1

∵ The perimeter of this playground is 27 feet

∴ P = 27

→ Equate the two values of P

∴ 4x - 1 = 27

→ Add 1 to both sides

∴ 4x - 1 + 1 = 27 + 1

∴ 4x = 28

→ Divide both sides by 4

∵ \frac{4x}{4} = \frac{28}{4}

∴ x = 7

→ Substitute the value of x in each side to find their lengths

∵ S1 = 2(7)

∴ S1 = 14 feet

∵ S2 = 7 - 1

∴ S2 = 6 feet

∵ S3 = 7 feet

∴ The lengths of the sides of the playground are 14 feet, 6 feet, 7 feet

7 0
2 years ago
The area of the shaded segment is 100cm^2. Calculate the value of r.
Reil [10]
Hello, 

The formula for finding the area of a circular region is: A=  \frac{ \alpha *r^{2} }{2}

then:
A_{1} = \frac{80*r^{2} }{2}

With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.

cos(40)= \frac{h}{r}  \\  \\ h= r*cos(40)\\ \\ \\ sen(40)= \frac{b}{r} \\ \\ b=r*sen(40)

Now we can find its area:
A_{2}=2* \frac{b*h}{2}  \\  \\ A_{2}= [r*sen(40)][r*cos(40)]\\  \\A_{2}= r^{2}*sen(40)*cos(40)

The subtraction of the two areas is 100cm^2, then:

A_{1}-A_{2}=100cm^{2} \\ (40*r^{2})-(r^{2}*sen(40)*cos(40) )=100cm^{2} \\ 39.51r^{2}=100cm^{2} \\ r^{2}=2.53cm^{2} \\ r=1.59cm

Answer: r= 1.59cm
7 0
2 years ago
Read 2 more answers
Help plzzzzzzzzzzzzzz ill give you 100 pts if you solve all of it​
Pachacha [2.7K]

Answer:

it is C but that is not 100 points :'(

Step-by-step explanation:

4 0
3 years ago
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