Before I put out my answer, I just want make note that sec() = 1 / cos() and csc () = 1 / sin ()
1) Once you distribute cos()sin() to sec(), the cos() will cancel out with the sec() to make it just sin(), and once cos()sin() is distributed to csc(), the sin() will cancel out with the cos()
2) After doing that you should just be left with sin() + cos()
3) And since no more simplification can be done, that is your answer :D
Answer:
Na+ and Cl- should be examples of an ion.
<Hope I answered your question>
Answer:
The number is 12
Step-by-step explanation:
[] First, let's turn all these words into something mathematical. N will equal "my number"
-><u> If you add 12 to my number</u> and then multiply the result by 3, you will get 64 more than two-thirds of my number.
-> n + 12 <u>and then multiply the result by 3</u>, you will get 64 more than two-thirds of my number.
-> 3(n + 12), you will get 64 more than <u>two-thirds of my number</u>.
-> 3(n + 12) = <u>64 more than</u> 
-> 3(n + 12) = 64 + 
[] Phew, okay. Now it is something we can solve and less scary;
[Given]
3(n + 12) = 64 + 
[Distribute]
3n + 36 = 64 + 
[Multiply both sides by 3]
9n + 108 = 192 + 2n
[Subtract 108 and 2n from both sides]
7n = 84
[Divide both sides by 4]
n = 12
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
Answer:
4. C
5. A
6. D
Step-by-step explanation: