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Romashka-Z-Leto [24]
3 years ago
7

Asappppppppp?????????????​

Mathematics
1 answer:
Alik [6]3 years ago
8 0
The answer is “+”
..........
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PLEASE HELP DUE IN LESS THAN 5 WILL MARK BRAINLIEST!!!!!!!!!!
RUDIKE [14]

Answer:

1. 1:4

2. y = 4 x X

3. yes

Step-by-step explanation:

1. every 1 minuet he cleans 4 shrimp

2. y is the number of shrimp and x is the time. if every miuet he cleans 4 shrimp, then that means you have to multiply the shrimp by the minuets. for example, if he spends 2 minuets, he cleans 8 shrimp because 2 x 4 = 8.

3. This is a proportional relationship because if you were to put this on a graph, it would be a strait line. for example, if you were to plot x (the time) on a line (this line would go horizontal) and y (shrimp) on the line (this line goes verticle) 1 minuet = 4 shrimp. 2 minuets = 8 shrimp. 3 minuets = 12 shrimp. 4 minuets = 16 shrimp.

i hope this helps. tell me if this is too confusing or if you need more help. have a great day :)

6 0
3 years ago
Help asap pls and ty
BabaBlast [244]
The answer I got is (-6,-2) the x value is -6
7 0
3 years ago
Read 2 more answers
Martin charges $10 for every 5 bags of leaves he rakes. Last weekend, he raked 2 bags of leaves. How much money did he earn?
Gnoma [55]
He earned 4 dollars. 
5 0
3 years ago
Read 2 more answers
What is the area of the following trapezoid?<br> 13.5 yd 2<br> 3.38 yd 2<br> 6.75 yd 2<br> 8.25 yd 2
Neporo4naja [7]

Answer:

area =  \frac{a + b}{2} h \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   =  \frac{2 + 7}{2}  \times 1.5 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 6.75 {yd}^{2}

8 0
3 years ago
US average math SAT scores follow a normal distribution with a mean of 505 and a standard deviation of 112. A sample of 64 enter
Hitman42 [59]

Answer:

The claim that the scores of UT students are less than the US average is wrong

Step-by-step explanation:

Given : Sample size = 64

           Standard deviation = 112

           Mean = 505

           Average score = 477

To Find : Test the claim that the scores of UT students are less than the US average at the 0.05 level of significance.

Solution:

Sample size = 64

n > 30

So we will use z test

H_0:\mu \geq 477\\H_a:\mu < 477

Formula : z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

z=\frac{505-477}{\frac{112}{\sqrt{64}}}

z=2

Refer the z table for p value

p value = 0.9772

α=0.05

p value > α

So, we accept the null hypothesis

Hence The claim that the scores of UT students are less than the US average is wrong

3 0
3 years ago
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