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3 years ago

Show your work in the comments below and the answer choice

Mathematics

1 answer:

murzikaleks [220]3 years ago

8 0

Answer: D

Step-by-step explanation:

Formula: A = 2(wl+hl+hw)

A = 2(5*3 + 7*3 + 7*5)

A = 2(15 + 21 + 35)

A = 2(71) = 142 sq inches

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Sam is hired for a 20-day period. On days that he works, he earns $60. For each day that he does not work, $30 is subtracted fro

Alenkinab [10]

Answer:

He did not work for 6 days

Step-by-step explanation:

Sam is hired for a 20-day period.

Let x be the no. of days he did not work

So, No. of days he worked = 20-x

he earns per working day = $60

So, he earns for (20-x) days = 60(20-x)

For each day that he does not work, $30 is subtracted from his earnings.

So, Amount deducted for x days = 30x

So, His earning for 20 days = $60(20-x)-30x$

We are given that At the end of the 20-day period, he received $660

So, $60(20-x)-30x=660$

$1200-60x-30x=660$

$1200-90x=660$

$1200-660=90x$

$540=90x$

$\frac{540}{90}=x$

$6=x$

So, he did not work for 6 days

So, Option C is true

5 0

3 years ago

A group of friends were working on a student film that had a budget of $1300. They used $546 of their budget on props. What perc

Umnica [9.8K]

Answer:

Step-by-step explanation:

trust me i had the same answer and it was right

6 0

2 years ago

Solve using Elimination 3x+y=-9 y=5x+7

valentinak56 [21]

Answer

x=-2 and y=-3

Step-by-step explanation:

Step: Solvey=5x+7for y:

Step: Substitute5x+7 for y in 3x+y=−9:

3x+y=−9

3x+5x+7=−9

8x+7=−9(Simplify both sides of the equation)

8x+7+−7=−9+−7(Add -7 to both sides)

8x=−16

8x/8=−16/8

(Divide both sides by 8)

x=−2

Step: Substitute−2 for x in y=5x+7:

y=5x+7

y=(5)(−2)+7

y=−3(Simplify both sides of the equation)

7 0

2 years ago

The function f(x) = 5One-fifth is reflected over the y-axis. Which equations represent the reflected function? Select two option

postnew [5]

Answer:

The equations that represent the reflected function are

$f(x)=5(\frac{1}{5})^{-x}$

$f(x)=5(5)^{x}$

Step-by-step explanation:

The correct question in the attached figure

we have the function

$f(x)=5(\frac{1}{5})^{x}$

we know that

A reflection across the y-axis interchanges positive x-values with negative x-values, swapping x and −x.

therefore

$f(−x) = f(x).$

The reflection of the given function across the y-axis will be equal to

(Remember interchanges positive x-values with negative x-values)

$f(x)=5(\frac{1}{5})^{-x}$

An equivalent form will be

$f(x)=5(\frac{1}{5})^{(-1)(x)}=5[(\frac{1}{5})^{-1})]^{x}=5(5)^{x}$

therefore

The equations that represent the reflected function are

$f(x)=5(\frac{1}{5})^{-x}$

$f(x)=5(5)^{x}$

9 0

2 years ago

Read 2 more answers

A, b, c, and d please

DIA [1.3K]

<h2>Answers / Step-by-step explanation:</h2><h3>a. What is the length of one side of the square.</h3>

Looking at the image, the radius (r) of the circle appears to cover half of the length of a side of the square. Hence, the side of the square has a length of 2r.

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<h3>b. The formula A= πr² is used to find the area of a circle. The formula A=4r² can be used to find the area of the square. Write the ratio of the area of the circle to the area of the square in the simplest form.</h3>

$Ratio=\frac{\pi r^{2} }{4r^2} =\frac{\pi}{4}$ .

Notice that the value "r²" disappears from the expression because is being multiplied and divided by it at the same time.

$Ratio=\frac{4\pi }{16} =0.7854.$

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c. Complete the table.

To complete each cell of the table, simply take the equation of the asked parameter and substitute the value of r by the number indicated in the title of the column. For example, column 3 should be filled out like this:

Area of Circle (units²): π(3)²or 9π.

Length of 1 Side of the Square: 2r= 2(3)= 6.

Area of Square (units²)= 4r²= 4(3)²= 36.

Ratio: $\frac{\pi}{4}$ .

Do the same for all the other columns.

The answers to the table are presented on the attached image.

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d. What can you conclude about the relationship between the area of the circle and the square?

They will always have the same value, π/4, regardless of the size of the square and circle. As long as the circle borders meet the square's at the middle of each side of the square, the relationship will be the same.

4 0

2 years ago