Answer:
Pretty Simple!
Now that you know about ratios and all that, this is pretty tame compared to the last problem.
Now, the problem is talking 2D(2 Dimensions)
The ratio is not going to work because it has only one parameter.
Thus, we need to square it!
Thus, we have your correct ratio.
Now, we only need to do the same thing for the triangle problem. Meaning that, we need to compare the ratios, with x as the thing we are looking for.
See? X is practically handed to us.
Hope this helps!
Given that ∠B ≅ ∠C.
to prove that the sides AB = AC
This can be done by the method of contradiction.
If possible let AB =AC
Then either AB>AC or AB<AC
Case i: If AB>AC, then by triangle axiom, Angle C > angle B.
But since angle C = angle B, we get AB cannot be greater than AC
Case ii: If AB<AC, then by triangle axiom, Angle C < angle B.
But since angle C = angle B, we get AB cannot be less than AC
Conclusion:
Since AB cannot be greater than AC nor less than AC, we have only one possibility. that is AB =AC
Hence if angle B = angle C it follows that
AB = AC, and AB ≅ AC.
