D
The domain is the x values, so the right side of the circle are the x’s.
Answer:
$595
e) If the company insures a large number of these cars, they can expect the average cost per car to be approximately E(C).
Step-by-step explanation:
Given the distribution :
C $0 $500 $1000 $2,000
P(C) 0.60 0.05 0.13 0.22
Expected probability : E(C)
Σ[C * P(C)] = (0*0.60) + (500*0.05) + (1000*0.13) + (2000*0.22) = $595
Since the expected value could be interpreted as the average value of a random variable over a large Number of experiment or trials
Sorry I am a little late...
a = -2
b = -9
Here is how to solve the problem.
First thing I did was multiply the first equation by -2 so that we can eliminate the the b. After you multiply it by -2, your new equation is -16a + 8b = -40.
You leave the second equation alone and all you do is combine like terms. So -16a+5a is -11. And you eliminate the b. Then you're going to do -40+62 which is 22. So it's -11a=22 and then you have to solve for a. What I did was I multiplied the whole thing by minus to turn the a positive. So then it's 11a=-22. Pretty easy, the final step is to simplify. -22/11 is -2. ;D
So there you have your first answer.
a = -2
Now we're going to use the first answer to help us find b.
For the second equation, all you're going to do is plug in that a.
5 (-2)-8b=62
-10 - 8b = 62
Now we move the -10 to the other side...
-8b = 62 + 10
-8b = 72
Multiply the whole thing by negative once again to turn the b positive.
Now we have 8b = -72
The final step is to simplify. -72/11 = -9
b = -9
Hope this makes sense! Also I had the same question on my test and I got it right. :)
The answer it -2
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Not enough info to answer the question it should have 2 trapezoids to compare if your talking about transformations