Domain is the x-values
Range is the y-values
To identify the range, plug in the x-values they gave you into the equation to find its y-value
x = 3
y = 2x + 4 Plug in 3 for x
y = 2(3) + 4
y = 10
x = 5
y = 2x + 4 Plug in 5 for x
y = 2(5) + 4
y = 10 + 4
y = 14
x = 6
y = 2x + 4 Plug in 6 for x
y = 2(6) + 4
y = 16
x = 8
y = 2x + 4 Plug in 8 for x
y = 2(8) + 4
y = 20
The range is {10, 14, 16, 20}
To solve for x, simply rearrange the problem:
Answer:
The answer is A and E
x2+(y−3)2=36
x^{2}+(y+8)^{2}=36x2+(y+8)2=36
Answer:
16 singles, 56 couples
Step-by-step explanation:
There's two linear equations that we can make: one for money and one for people.
Let the number of single tickets be s and the number of couple tickets be c
.
We know that the amount of money we make is $ = 20
s
+
35
c
=
2280
We also how many people can come P =
1
s
+
2
c
=
128
We know that both s are the same and both c are the same. We have two unknowns and two equations, so we can do some algebra to solve for each.
Take the first minus twenty times the second:
20
s
+
35
c =2280
−
20
s
−
40
c
=
−
2560
−
5
c
=
−
280
⇒
c
=
56
Plugging this back into the second equation,
s
+
2
c
=
s
+
2
⋅
56
=
s
+
112
=
128
⇒
s
=
16
Answer:
9/7 or 1 2/7
Step-by-step explanation:
use the formula rise/run
