To find the area of a quarter circle, you simply take a quarter of a full circle. As all quarters are equal, this means that the formula would be <span><span>π<span><span>r2</span>4</span></span><span>π<span><span>r2</span>4</span></span></span><span>. But wait, there's more. If you notice, </span><span><span>π<span><span>r2</span>4</span>=π<span><span>r2</span>2</span></span><span>π<span><span>r2</span>4</span>=π<span><span>r2</span>2</span></span></span><span>. This coincides with the circle formula, just with half the radius. Notice anything? A quarter of a circle can be calculated in the same way a circle a quarter the size can. This means that a quarter circle is equal to a circle a quarter size. In this same way, a ninth of a circle is equal to a circle of one ninth the size.</span>
All you have to do is 431.2 divided by 24.5
Hope this helps
Answer:
X= 1 AND 13
Step-by-step explanation:
x2+14x = -13
by completing the square method
you add the square of half the coefficient of b to both sides
which is (14/2)^2
x^2+14x+(7^2) = -13 +(7^2)
x^2 + 7^2 = -13 + 49
x^2 + 7^2 = 36
(x + 7)^2 = 36
find the square root of both sides
(x+7) = + or - 6
x=7-6 ; 1
or
x= 7+6 ; 13
Answer:
D
Step-by-step explanation:
According to remainder theorem, you can know the remainder of these polynomials if you plug in x = -6 into them.
<em>So we will plug in -6 into x of all the polynomials ( A through D) and see which one equals -3.</em>
<em />
<em>For A:</em>
For B:
For C:
For D:
The only function that has a remainder of -3 when divided by x + 6 is the fourth one, answer choice D.
Answer:
number of dimes 11 to 14
Step-by-step explanation:
given data
coin = 19
worth no less = $1.30
Nolan nickles = 5
solution
we convert 5 cent to dollars, it will be
5÷100 = $0.05
and
dime is worth 10 cents
so it will be 10 ÷ 100 = $0.1
so we consider here x as the number when nickels.
and we consider y as the number of dimes.
so here we can say
x + y ≤ 19 ..........................1
as here no less than $1.30 combined.
so
0.05 x + 0.1 y ≥ 1.3 ......................2
and
when Nolan has 5 nickels
put x = 5 in eq 1
5 + y ≤ 19
y ≤ 19 - 5
y ≤ 14
and
now we put x = 5 in eq 2
0.05 × 5 + 0.1y ≥ 1.3
0.25 + 0.1y ≥ 1.3
0.1y ≥ 1.3 - 0.25
0.1y ≥ 1.05
y ≥ 10.5
so all possible values for the number of dimes 11 to 14
