periodic deposit of 3000 at the end of each year with a rate of 3.5 compounded annually for 10 years will have how much money
1 answer:
Yaya
compound interetest
for compounded annually
A=future amount
P=present amount
waait, we need to add 3000 per month
anyway, each year, we multiply by 1+3.5%=1+0.035=1.035
so
add 3000, multiply by 1.035
add 3000, multiply by 1.035
repeat until yo did it 10 times
, you get the idea
anyway, the answer is 36426.9757
rounded, it's about $36426.98
the sum will be
compound interetest
for compounded annually
A=future amount
P=present amount
waait, we need to add 3000 per month
anyway, each year, we multiply by 1+3.5%=1+0.035=1.035
so
add 3000, multiply by 1.035
add 3000, multiply by 1.035
repeat until yo did it 10 times
anyway, the answer is 36426.9757
rounded, it's about $36426.98
the sum will be
You might be interested in
you'll first need to understand the symbols, I've attched a cheat sheet :)
you'll need to see if AB is linked to CD reversed.
If not then it's not A
For B you'll have to see if the angles are parralel to each other.
and for C you'll have to see if the angles are the same.
and D is the same as C
so the answer is ab=cd
<h2>now you understand :)</h2>
Answer:
Step-by-step explanation:
Given equation of line is:
y = -4x+9
Comparing it with the standard form
y = mx+b
m = -4
As we know that the product of slopes of perpendicular lines is -1
Let m1 be the slope of perpendicular line
m * m1 = -1
-4 * m1 = -1
m1 = -1/-4
m1 = 1/4
In order to find the value of b, putting the point in standard form
5 = (1/4)*4 + b
5 = 1 + b
b = 5-1
b = 4
Putting the value of b and m1 in standard form
..