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Vesnalui [34]
3 years ago
10

Please answer correctly! I will Mark you as Brainliest!

Mathematics
1 answer:
densk [106]3 years ago
5 0

Answer:

Im pretty sure its 7 but wait for someone else to awnser id.k if i did my math correctly or not lol

Step-by-step explanation:

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Mrs. Adams deposited $12,000 into an account that earns an annual simple interest rate of 3.25%. She makes no other deposits or
lisabon 2012 [21]

Answer:

<em>Mrs. Adams will earn $3,120 of interest at the end of year 8.</em>

Step-by-step explanation:

<u>Simple Interest</u>

In simple interest, the money earns interest at a fixed rate, assuming no new money is coming in or out of the account.

We can calculate the interests earned by an investment of value A in a period of time t, at an interest rate r with the formula:

I=A.r.t

Mrs. Adams deposited an amount of A=$12,000 into an account that earns an annual simple interest rate of r=3.25%. We must find the interest earned in t=8 years. The interest rate is converted to decimal as:

r=3.25/100=0.0325

The interest is then calculated:

I=12,000\cdot 0.0325\cdot 8=3,120

Mrs. Adams will earn $3,120 of interest at the end of year 8.

7 0
3 years ago
Suppose that a college determines the following distribution for X = number of courses taken by a full-time student this semeste
lidiya [134]

Answer:

E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74In order to find the variance we need to calculate first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36And the variance is given by:

Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924

And the deviation would be:

Sd(X) =\sqrt{0.8924} =0.9447

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).  

Solution to the problem

For this case we have the following distribution given:

X          3      4       5        6

P(X)   0.07  0.4  0.25  0.28

We can calculate the mean with the following formula:

E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74

In order to find the variance we need to calculate first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36

And the variance is given by:

Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924

And the deviation would be:

Sd(X) =\sqrt{0.8924} =0.9447

3 0
3 years ago
Jane drinks one-fourth of a gallon of soda every three days. If they continue to drink the same
zhenek [66]

Answer:

0.83 gallons of soda

7 0
3 years ago
IF U SEE THIS HELP PLEASE!!!
pshichka [43]

Answer:

I have the pictures of the whole answer  book if you want to see them add me on disco

Step-by-step explanation:

6 0
3 years ago
The data set represents the number of rings each person in a room is wearingin arena
anastassius [24]

Answer:

<u>2</u>

Step-by-step explanation:

<u>0</u>, 0, <u>2</u>, 2, <u>2</u>, 3, <u>4</u>, 6, <u>8</u>

Min=0. Max=8. Median=2. LQ=2

UQ=4

4-2=<u>2</u>

8 0
3 years ago
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