3 years ago

Which numbers are perfect squares? Determine their square roots. 5 20 16 49

Mathematics

1 answer:

Yakvenalex [24]3 years ago

7 0

Answer: Only 16

Step-by-step explanation:

The square roots of 5 & 20 are long decimals.

The square root of 49 is 7 but 7 has a decimal square root.

The square root of 16 is 4, 4 is 2 squared.

So 16 is a perfect square.

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Please help me!!!!! :)

lora16 [44]

6 / (x + 6) = 10/15

10(x+6) = 90

10x + 60 = 90

10x = 30

x = 3

7 0

3 years ago

Choose the correct simplification of the expression (3x)^4.

Y_Kistochka [10]

The exponent 4 needs to be applied to both 3 and x, so we would have:
3 * 3 * 3 * 3 * x^4.
9 * 9 * x^4.
81x^4

6 0

3 years ago

Read 2 more answers

Given X(0, 2), Y(-2, 2), and Z(-2, 0), find the coordinates of X', Y', and Z' after a dilation with scale factor -4.

kotykmax [81]

Answer:

what is the origin of the dilation?

3 0

3 years ago

What is the area of the figure shown below?

german

Área of rectangle= 18 x 14 = 252

Area or triangle=
30-18= 12
12 is the base of the triangle
14 is the height of the triangle
Area of a Triangle= 1/2bh
1/2(12)(14)=84
Área of Triangle= 84

252+84= 336

Answer= 336

4 0

2 years ago

State restrictions for the given equation below

Genrish500 [490]

The restriction of the given equation is $cos^{2}x =cos^{2} x$ , other than 0≤x≤2π.

What is restriction of equation?

Restriction of the equation is the value of domain where the value is limited.

Given,

$sin^{2} xcos^{2}x +cos^4x =(1-sinx)(1+sinx)$

taking $cos^2x$ common, we get

$cos^2x(sin^2x+cos^2x)=1+sinx-sinx-sin^2x$

we know

$sin^2x+cos^2x=1\\cos^2x=1-sin^2x$

we get,

$cos^2x=cos^2x$

and the restriction is 0≤x≤2π.

To know more restriction, visit:

brainly.com/question/68084

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8 0

1 year ago