Pls help with alg II dying

At the fair, 2 corn dogs and 3 pretzels cost $13, and 5 corn dogs and 6 pretzels costs $28. How much

NemiM [27]

Let x represent the cost of corn dogs. Let y represent the cost of pretzels.

2x+3y=13
5x+6y=28

Multiply the first equation by two so that we can eliminate y.

Subtract:
4x+6y=26
5x+6y=28

-x=-2
x=2

4(2)+6y=26
8+6y=26
6y=18
y=3

3 x 2 = 6
6+2=8

Therefore, 2 pretzels and a corn dog would cost $8.

5 0

2 years ago

Help me .......is urgent ,,,,,The point-slope equation for a given line may look different than the slope-

Reil [10]

Awnser- True

because the point slope is intercepted

5 0

2 years ago

Read 2 more answers

22. Francisco is three years more than twice Jenna's age. Harrison is two years less than three times Jenna's age.

Jet001 [13]

Answer:

An expression for Francisco's age in terms of a is (2a+3)

An expression for Harrison's age in terms of a is (3a-2)

An expression for the sum of all three ages, in terms of a is (6a+1)

Step-by-step explanation:

Let

a -----> Jenna's age

b -----> Francisco's age

c -----> Harrison's age

we know that

Francisco's age is two times Jenna's age plus three years

b=2a+3 -----> equation A

Harrison's age is three times Jenna's age minus two years

c=3a-2 ----> equation B

The sum of all three ages, in terms of a is

(a+b+c) -----> equation C

substitute equation A and equation B in equation C

a+(2a+3)+(3a-2)

Combine like terms

(a+2a+3a)+(3-2)

6a+1

therefore

An expression for Francisco's age in terms of a is (2a+3)

An expression for Harrison's age in terms of a is (3a-2)

An expression for the sum of all three ages, in terms of a is (6a+1)

6 0

3 years ago

A rectangular piece of plywood has a diagonal which measures two feet more than the width. The length of the plywood is twice th

icang [17]

Answer:

The length of the plywood's diagonal(to the nearest tenth) is, 3.6 and 1.4

Step-by-step explanation:

let l be the length and w be the width of the rectangle respectively;

Diagonal(D) of a rectangle is given by:

$D = \sqrt{l^2+w^2}$ ......[1]

As per the given statement we have;

Diagonal(D) = width + 2

and

$l = 2 \times w$ = 2w

Now, substitute these in [1] we have;

$\sqrt{(2w)^2+w^2} = w+5$

Squaring both the sides we get;

$4w^2+w^2 = (w+2)^2$

$5w^2 = w^2 + 4 + 4w$

or

$5w^2 -w^2 = 4w + 4$ or

$4w^2= 4w + 4$

Simplify:

$w^2-w-1 =0$ ......[2]

The quadratic equation is in the form of $ax^2+bx+c = 0$

the solution is given by: $x = \frac{-b \pm\sqrt{b^2-4ac}}{2a}$

On comparing with [1] we get

a= 1 , b = -1 and c = -1

Then the solution is:

$w= \frac{-(-1) \pm\sqrt{(-1)^2-4(1)(-1)}}{2(1)}$

$w =\frac{1 \pm\sqrt{1+4}}{2} = \frac{1 \pm\sqrt{5}}{2}$

Simplify:

$w \approx 1.62$ and $w \approx -0.62$

Then, the diagonal D = w+2

For $w \approx 1.62$

$D = 1.62 +2 \approx 3.62$

For $w \approx -0.62$

$D =-0.62 +2 \approx 1.38$

therefore, the length of the plywood's diagonal(to the nearest tenth) is, 3.6 and 1.4

5 0

2 years ago

How do you do this problem ?

miskamm [114]

You could do all of the work with the multiplying, but what I think it wants you to see is that you can divide like numbers by subtracting exponents.

so if we did that we would get $(-2^{2})(-3^3)(-5^1)$

this in turn would give us 4 x -9 x -5 = 180

6 0

2 years ago