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Angelina_Jolie [31]

3 years ago

9

What is the area of this shape

2 answers:

zhannawk [14.2K]3 years ago

6 0

No picture display.

Anna11 [10]3 years ago

4 0

Which shape there is nothing

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The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?

Serhud [2]

Answer:

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

Step-by-step explanation:

Given - The circumference of the ellipse approximated by $C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }$ where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

$C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi } = \sqrt{\frac{a^{2} + b^{2} }{2} }$

Squaring Both sides, we get

$[\frac{C}{2\pi }]^{2} = [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2} } = {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2} } = {{a^{2} + b^{2} }$

$\frac{C^{2} }{2(\pi )^{2} } = a^{2} + b^{2} \\\frac{C^{2} }{2(\pi )^{2} } - a^{2} = b^{2} \\\sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}} = b$

∴ we get

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

8 0

3 years ago

Please help! Write the intervals of the values shown on the graph below

Veseljchak [2.6K]

The answer is
-1 ≤ x < 3
We just learned this is in my algebra 2 AP class

5 0

3 years ago

What’s two plus two times 9 sixteen times

anastassius [24]

576

Explanation: 2+2 = 4

4x9 = 36

36x16 = 576

Pls mark brainliest!

4 0

3 years ago

Read 2 more answers

An antelope can run at a speed of 42 miles per hour.How many feet per second is tgis?

coldgirl [10]

An antelope can run at a speed of 42 miles per hour.How many feet per second is this?
Answer:61.6 feet per second.

5 0

4 years ago

Determine la ecuación general de la recta que pasa por los puntos (1,4); (- 2, - 5) y grafíquela.

Rudiy27

The equation of the line that passes through the points (1 , 4) and (-2, -5) is y = 3x + 1

<h3>Further explanation</h3>

Solving linear equation mean calculating the unknown variable from the equation.

Let the linear equation : y = mx + c

If we draw the above equation on Cartesian Coordinates , it will be a straight line with :

<em>m → gradient of the line</em>

<em>( 0 , c ) → y - intercept</em>

Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :

$\large {\boxed {m = \frac{y_2 - y_1}{x_2 - x_1}} }$

If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :

$\large {\boxed{y - y_1 = m ( x - x_1 )} }$

Let us tackle the problem.

Let :

(1 , 4) → (x₁ , y₁)

(-2, -5) → (x₂ , y₂)

To find the straight line equation, the following formula can be used :

$\frac{y - y_1}{y_2 - y_1} = \frac{x - x_1}{x_2 - x_1}$

$\frac{y - 4}{-5 - 4} = \frac{x - 1}{-2 - 1}$

$\frac{y - 4}{-9} = \frac{x - 1}{-3}$

$\frac{y - 4}{3} = \frac{x - 1}{1}$

$y - 4 = 3 ( x - 1 )$

$y = 3x - 3 + 4$

$\large {\boxed {y = 3x + 1} }$

<h3>Learn more</h3>

Infinite Number of Solutions : brainly.com/question/5450548
System of Equations : brainly.com/question/1995493
System of Linear equations : brainly.com/question/3291576

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Linear Equations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point

4 0

4 years ago