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3 years ago

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Find the lateral area of the cylinder. Give your answer in terms of pi

1 answer:

Artist 52 [7]3 years ago

7 0

Answer:

<h2>204π units²</h2>

Step-by-step explanation:

The lateral area of the cylinder includes both the side and the ends.

The area of the side can be found by calculating the circumference of the cylinder and multiplying that by the height: A = 2π(6 units )(11 units) = 132π units².

The area of one end of this cylinder can be found by applying the "area of a circle" formula: A = πr². Here, with r = 6 units, A = π(6 units)² = 36π units². Since the cylinder has two ends, the total area of the ends is thus 2(36π units) = 72π units.

The total lateral area of the cylinder is thus 72π units² + 132π units², or 204π units²

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The hypotenuse of a right triangle is 14 centimeters long. One of the legs of the triangle is 6 centimeters. What is the length

BartSMP [9]

Answer: 12.65 cm

Step-by-step explanation:

Use the Pythagoras theorem,

a^2 + b^2= c^2

You are given the hypotenuse , which is c and another leg which is either a or b, does not particularly matter- rearrange to find the missing length

c^2 - b^2 = a^2

14^2 - 6^2 = 160

Square root 160 to find the missing length

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Answer:

Angle of A = 90 degree-62 degree = 28 degree.

Step-by-step explanation:

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Zuma earns $12.50 an hour. How many hours must she work to earn $500?

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Step-by-step explanation:

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A town is planning a playground. It wants to fence in a rectangular space using an existing wall. What is the greatest area it c

777dan777 [17]

Answer:

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Step-by-step explanation:

We are given that the playground is fenced on three sides of the playground and the four side has an existing wall.

Let the length of the rectangle be 'X' feet and width be 'Y' feet.

As the fencing is done using 100 feet of fence. We get the relation between the sides and the fence as, X + 2Y = 100.

As, X + 2Y = 100 → X = 100 - 2Y

Now, the area of the rectangle = XY = X × ( 100 - 2Y ).

i.e Area of the rectangle = $-2Y^{2} +100Y$ .

The general form of a quadratic equation is $y=ax^{2}+bx+c$ .

The maximum value of a quadratic equation is given by $x=\frac{-b}{2a}$ .

Therefore, the greatest value of $-2Y^{2} +100Y$ is at Y = $\frac{-100}{2 \times -2}$ = $\frac{-100}{-4}$ = 25.

Thus, Y = 25 and X = 100 - 2Y → X = 100 - 2 × 25 → X = 50.

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