You have that situation with ANY base that's less than ' 1 '.
Examples:
(0.9)² = 0.81 (90% of the base)
(7/8)² = 0.765625 (87.5% of the base)
(1/2)² = 1/4 (50% of the base)
(0.1)² = 0.01 (10% of the base)
Each of these results is less than the base, and with
higher positive powers, they keep getting smaller.
Answer:
incomplete
Step-by-step explanation:
please send the full information, I can't see students belonging to acers
This is not correct. It is not taking into account the 150 employees.
Answer:
Step-by-step explanation:
So, the function, P(t), represents the number of cells after t hours.
This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.
C)
So, we are given that the quadratic curve of the trend is the function:
To find the <em>instanteous</em> rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:
![\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%5BP%28t%29%5D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B6.10t%5E2-9.28t%2B16.43%5D)
Expand:
![P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]](https://tex.z-dn.net/?f=P%27%28t%29%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B6.10t%5E2%5D%2B%5Cfrac%7Bd%7D%7Bdt%7D%5B-9.28t%5D%2B%5Cfrac%7Bd%7D%7Bdt%7D%5B16.43%5D)
Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:
![P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]](https://tex.z-dn.net/?f=P%27%28t%29%3D6.10%5Cfrac%7Bd%7D%7Bdt%7D%5Bt%5E2%5D-9.28%5Cfrac%7Bd%7D%7Bdt%7D%5Bt%5D)
Differentiate. Use the power rule:
Simplify:
So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:
Multiply:
Subtract:
This tells us that at <em>exactly</em> t=5, the rate of growth is 51.72 cells per hour.
And we're done!
This is an exponential equation that can be represented by the following:
f(x) = a(b)^x
In this case...
25143 = a(0.66)^3
25143 is the population after 3 hours.
3 is the amount of time in hours.
0.66 represents the percent of the population remaining after each hour (66% as there is a 34% decline each hour).
We must solve for a, which is the initial population.
First, simplify (0.66)^3 to 0.2874.
25143 = 0.2874a
Now divide both sides by 0.2874 to isolate a.
a = 87455
There were initially 87,455 people within the city. I wouldn't want to be in that place!
