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Oksana_A [137]
3 years ago
7

Expand to write an equivalent expression: -1/4(-8x+12y)

Mathematics
1 answer:
kaheart [24]3 years ago
4 0

Answer:

Step-by-step explanation:

-1/4(-8x+12y)

-1*(-8x+12y)/4

8x-12y/4

4(2x-3y)/4(4 and 4 gets cancel)

2x-3y

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8:54 a.m.
dimaraw [331]
Hello,

The two lights flash at the same time every 18 min
at 8:00 h=480 min =480+0*36
at 8:36 h=516 min =480+1*36
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54 is not divisible by 36
60+12=72 = 2*36 yes
60+24=84 not
120+24=4*36 yes
180+18=198 not

So 2 times are correct 9:12 and 10:24
Answer G


 

5 0
3 years ago
Helpp- question linked below
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1 year ago
What is the average rate of change from 0 to 2 of f(x)=x^3-x+4​
Kay [80]

\mathbf{Task.} ~ \mathrm{What~is~the~average~rate~of~change~from~0~to~2~of~} f(x) = x^{3} - x + 4?

\mathrm{The~average~rate~} \upsilon ~ \mathrm{of~change~of~the~function~} f(x) ~ \mathrm{over~the~interval~} [x_{1}; \ x_{2}]\\\mathrm{can~be ~ found~on~the~formula \colon}

\boxed{\upsilon = \dfrac{\Delta f}{\Delta x} = \dfrac{f(x_{2}) - f(x_{1})}{x_{2} - x_{1}}  }

\mathrm{For~the~function,} ~ f(x) = x^{3} - x + 4 ~ \mathrm{the~average~rate~of~change~over~the~interval}\\\mathrm{from~0~to~2 \colon}

f(0) = 0^{3} -0 + 4 = 4;

f(2) = 2^{3} - 2 + 4 = 8 + 2 = 10;

\Delta f = 10 - 4 = 6;

\Delta x = 2 - 0 = 2.

\upsilon  = \dfrac{6}{2} = 3.

Answer \colon 3~\blacktriangle

3 0
3 years ago
Solve 2x – 6y = 4 for x.
MArishka [77]

Answer:

A

Step-by-step explanation:

bro how come u dont answer for yourself? The point of school is for you to learn. . . but anyway the answer is A

5 0
3 years ago
Jordan estimated that his paper airplane would fly 42 feet. It actually traveled 50 feet. What was the percent error?
topjm [15]

\huge \mathcal{ Answer࿐}

  • Error (e) = 50 - 42 = 8 feet

  • assumed value (a) = 42 feet

\boxed{ \mathrm{ \% \: error =  \dfrac{error}{assumed \: value}  \times 100}}

  • \mathrm{ \% \: error  =\dfrac{8}{42}}  \times 100

  • \mathrm{ \% \: error  = \dfrac{800}{42} }

  • \mathrm{ \% \: error  = 19.04 \%}

_____________________________

\mathrm{ \#TeeNForeveR}

6 0
3 years ago
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