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Answer:
Third option. x = 2, and x = 4.
Step-by-step explanation:
Find the zeros of this quadratic equation by factoring:
f(x) = x² - 6x + 8
Becomes:
f(x) = (x - 4)(x - 2)
Set each factor equal to 0 to solve for the roots;
x - 4 = 0
x = 4
x - 2 = 0
x = 2
Therefore, the zeros of this equation are at x = 2, and x = 4.
I got 20.8 and in fraction form it would be 20 4/5
Answer:
The enlargement will be 25 times and the enlargement area will be 
.
Step-by-step explanation:
It is given that each grid unit is equal to 3 inches. SO we have to use this scale.
The total height of the scale drawing is 21 inch and the enlargement has a height given as 105 inches. Therefore it has scale factor of 5. It means that each dimension is enlarged by 5 times the dimension in the scale drawing. So the enlargement of the logo will be 25 times and the enlargement area will be 2250 square inches.
The coefficient is 126 because 9 times 14 is 126
The electrical resistance of a wire varies as its length and inversely as the square of the diameter.
R = (k*L)/(d^2)
where k = proportionality constant
Since the two wires have the same material, their proportionality constant is same.
Equating that
(R1*d1^2)/L1 = (R2*d2^2)/L2
Given that R1 = 10 ohms, d1 = 1.2 mm or 0.0012 m, L1 = 18 m, d2 = 1.5 mm or 0.0015 m, L2 = 27 m, and R2 is unknown.
Therefore
[10*(0.0012^2)]/18 = [R2*(0.0015^2)]/27
R2 = 9.6 ohms
