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Stells [14]
3 years ago
13

A.(x-6, y-5). B.(x.-5, y-6) c.(x+5, y+6). D.(x+ 6, y+5)

Mathematics
2 answers:
Andru [333]3 years ago
7 0
Answer: C : (x+5, y+6)

Regards, Splinx <3
Svet_ta [14]3 years ago
6 0

Answer:

c. (x+5, y+6)

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aniked [119]

Answer:

the answer is 9.7×10 to the fourth power

Step-by-step explanation:

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3 years ago
Dependent events can best be described as
dem82 [27]

Answer:

Sonya watched

1

3

of a movie in the morning, and she watched some more at night. By the end of the day, she still had

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of the movie left to watch. How much of the movie did Sonya watch at night?

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
Voltage sags and swells. Refer to the Electrical Engineering (Vol. 95, 2013) study of transformer voltage sags and swells, Exerc
Artist 52 [7]

Answer:

a. z-score for the number of sags for this transformer is  ≈ 1.57 . The number of sags found in this transformer is within the highest 6% of the number of sags found in the transformers.  

b. z-score for the number of swells for this transformer is ≈ -3.36. The number of swells found in the transformer is extremely low and within the lowest 1%

Step-by-step explanation:

z score of sags and swells of a randomly selected transformer can be calculated using the equation

z=\frac{X-M}{s} where

  • X is the number of sags/swells found
  • M is the mean number of sags/swells
  • s is the standard deviation

z-score for the number of sags for this transformer is:

z=\frac{400-353}{30} ≈ 1.57

the number of sags found in the transformer is within the highest 6% of the number of sags found in the transformers.  

z-score for the number of swells for this transformer is:

z=\frac{100-184}{25} ≈ -3.36

the number of swells found in the transformer is extremely low and within the lowest 1%

5 0
3 years ago
I don't know what to do or how to do it ​
OleMash [197]

Answer:

i think you multiple the measure

3 0
3 years ago
Read 2 more answers
Assume that the red blood cell counts of women are normally distributed with a mean of 4.577 million cells per microliter and a
serg [7]

Answer:

82.31% of women have red blood cell counts in the normal range from 4.2 to 5.4 million cells per​ microliter

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 4.577, \sigma = 0.382

Approximately what percentage of women have red blood cell counts in the normal range from 4.2 to 5.4 million cells per​ microliter?

This is the pvalue of Z when X = 5.4 subtracted by the pvalue of Z when X = 4.2. So

X = 5.4

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.4 - 4.577}{0.382}

Z = 2.15

Z = 2.15 has a pvalue of 0.9842

X = 4.2

Z = \frac{X - \mu}{\sigma}

Z = \frac{4.2 - 4.577}{0.382}

Z = -0.99

Z = -0.99 has a pvalue of 0.1611

0.9842 - 0.1611 = 0.8231

82.31%  of women have red blood cell counts in the normal range from 4.2 to 5.4 million cells per​ microliter

3 0
3 years ago
Read 2 more answers
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