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djverab [1.8K]
3 years ago
12

Two athletes Or training over a two week period to increase the number of push-ups each can do consecutively . Athlete a can do

16 push-ups to start and increase his total by each to each day. Athlete b can do 12 push-ups to start an increase he's so tall by three each day. Compare the initial values for each what does the initial value mean in the situation
Mathematics
1 answer:
Naya [18.7K]3 years ago
5 0

Answer:

Initial values of Athlete a and b is 16 and 12 respectively. That means, Athlete a start with more push-ups as compared to athlete b

Step-by-step explanation:

Athlete a perform 16 push-ups  to start and increase 1 push-up each day for 14 days

⇒ number of push-ups at the end of x days is for Athlete A is

n = number of push-ups for athlete A= 16 + x

Athlete b perform 12 push-ups  to start and increase 3 push-up each day for 14 days

⇒ number of push-ups at the end of x days is for Athlete B is

m = number of push-ups for athlete B = 12 + 3x

where x is the number of days

thus, total number of athletes at the end of 14 day is

n = 16+14 = 30 push-ups for athlete A and m = 12 + 42 = 54 push-ups for athlete B at the end of 14th day

Now similarly for the initial day x = 0

thus, total number of athletes at the starting of 1st day is

n = 16+0 = 16 push-ups for athlete A and m = 12+0 =12 push-ups for athlete B at the starting of 1st day.

That means, Athlete a start with more push-ups as compared to athlete b, But at the end of 14th day Athlete b do more push-ups then athlete a

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Braxton has money in a savings account. The equation B = 800(1 + 0.03) can be used to calculate the amount
Sav [38]

Answer:

Braxton's initial investment is equals to (=) Pam's initial investment.

The interest on Braxton's account is less than (< ) the interest on Pam's account.

Step-by-step explanation:

Given - Braxton has money in a savings account. The equation

            B = 800(1 + 0.03)^{t} can be used to calculate the amount of money    

           in dollars, B, Braxton has in his account after t years since opening

           the account.

           Pam also has money in a savings account. The equation

           P=800(1 + 0.04)^{t}  can be used to calculate the  amount of money in

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To find - Braxton's initial investment ..........Pam's initial investment.

             The interest on Braxton's account .....the interest on Pam's account.

Proof -

As given, Broxton equation is - 800(1 + 0.03)^{t}

               Pam equation is - 800(1 + 0.04)^{t}  

Now,

1.)

For initial investment , Put t = 0

⇒B = 800(1 + 0.03)^{0} = 800(1) = 800

  P =  800(1 + 0.04)^{0} = 800(1) = 800

As for t = 0

Braxton's equation , B = Pam's equation,P

⇒Braxton's Initial investment = Pam's initial investment.

2.)

For the interest,

As we don not have time for which the interest has to be check.

So , let the time period = 5 years

Therefore,

B = 800(1 + 0.03)^{5} = 800(1.03)^{5} = 800(1.1593) = 927.42

P =  800(1 + 0.04)^{5} = 800(1.04)^{5} = 800(1.2166) = 973.32

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Interest on Braxton's account = 927.42 - 800 = 127.42 ≈ 127

Interest on Pam's account = 973.32 - 800 = 173.32 ≈ 173

∴ we get

The interest on Braxton's account is less than the interest on Pam's account.

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