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enot [183]
3 years ago
8

Ill give you brainliest>>>Write an equation of the line passing through the point (5, 2) that is perpendicular to the l

ine −x+3y=12.
The equation of the line is y= x+
Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
6 0

y= mx+b

(16, -7) = (x,y)

2(16) - 3y = 12

32 - 3y = 12

32 - 12 = 3y

20/3 = y

6.6 = y

2x-3(-7) = 12

2x+21 = 12

2x = 12 - 21

x = -9/2

Insert the values into y = mx + b

solve for m and then solve for b

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Find the slope of the line that passes through the points (0,-11) and (8,-8).
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To find the slope of a line, we can use the following formula:

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m-term stands for slope or gradient. The formula is useful whenever you want to find a slope of two points.

Let these be the following:

\displaystyle \large{(x_1,y_1) = (0, - 11)} \\  \displaystyle \large{(x_2,y_2) = (8, - 8)}

Substitute the points in formula:

\displaystyle \large{m =  \frac{ - 8 -( - 11)}{ 8 - 0} }

Negative multiply negative always come out as positive.

\displaystyle \large{m =  \frac{ - 8  +  11}{ 8 - 0} } \\  \displaystyle \large{m =  \frac{ 3}{ 8 } } \\

Since m stands for slope, we can say that:

\displaystyle  \large \boxed{ \tt{slope  =  \frac{3}{8} }}

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