A box contains 10 transistors, 4 of which are defective. If 3 are sold at random, find the probability that exactly 1 are defect
1 answer:
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Answer:
The points for the given two linear equation as
= - 2 , - 6
= - 2 , 6
The graph so plotted as shown
Step-by-step explanation:
Given as :
The two linear equation are
y = 3 x ........A and
y = - x - 8 .........B
Solving equation A and B
Now, Put The value of y from eq A into eq B
So, 3 x = - x - 8
Or, 3 x + x = - 8
Or, 4 x = - 8
∴ x =
I.e x = - 2
Now , Put the value of x into eq A
∵ y = 3 x
∴ y = 3 × (-2)
I.e y = - 6
Again, Put the value of x into eq B
∵ y = - x - 8
∴ y = - 2 - (-8)
I.e y = 6
So, for x = - 2 , y = - 6
And for x = - 2 , y = 6
Hence , The points for the given two linear equation as
= - 2 , - 6
= - 2 , 6
The graph so plotted as shown . Answer
