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3 years ago

Can synthetic materials cause problems for society? Explain your answer.

2 answers:

7 0

Absolutely. Synthetic materials which are by-products of petroleum are non-biodegradable, synthetic products take a long time to decompose, creating long-term pollution. Nylon is hard to recycle, making them hard to decompose, accumulate landfills more. Polyesters are easy to recycle, which makes them less harmful to the society.

scoray [572]3 years ago

4 0

Answer:

Yes

Explanation:

Synthetic materials which are by-products of petroleum are non-biodegradable, synthetic products take a long time to decompose, creating long-term pollution. Nylon is hard to recycle, making them hard to decompose, accumulate landfills more. Polyesters are easy to recycle, which makes them less harmful to the society.

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equal volumes of equimolar aqueous solutions of sodium sulfite and hydroiodic acid are mixed. what net ionic equation describes

erica [24]

Na₂S₂O₃(aq) + 2HCl(aq) → 2NaCl(aq) + H₂O(l) + SO₂(g) + S(s). A light yellow precipitate develops as the process continues.

<h3>What does the chemistry term "equation" mean?</h3>

Reaction equation are symbolic depictions of chemical reactions where the reactants and products are stated in relation to the following chemical formulae.

<h3>Equation and response are what?</h3>

What is an equations and a chemical reaction? In a chemical change, bonds between molecules of the reagent are destroyed and new bonds between molecules of the product are established to create a new substance. A chemical formula is nothing more than a statement of fact that represents how reactants generate products.

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4 0

1 year ago

I need an answer ASAP

Oduvanchick [21]

Time taken for star to reach Earth = 7.5 years

<h3>Further explanation</h3>

Given

7.5 light years(distance Earth-star)

Required

Time taken

Solution

Speed of light=v = 3 x 10⁸ m/s

1 light years = 9.461 × 10¹⁵ m= distance(d)

So time taken for 1 light years :

time(t) = distance(d) : speed(v)

t = 9.461 × 10¹⁵ m : 3 x 10⁸ m/s

t = 3.154 x 10⁷ s = 1 years

So for 7.5 light years, time taken = 7.5 years

8 0

3 years ago

What mass of oxygen reacts with 4.62 g of magnesium to form magnesium oxide according to the following... 2 Mg O2 --> MgO

Goryan [66]

Answer:

3.08 g of Oxygen .

Explanation:

2Mg + O₂ = 2MgO

2 mole 1 mole

molecular weight of Mg = 24

2 mol of Mg = 48 g

48 g of Mg reacts with 32 g of oxygen

4.62 g of Mg will reacts with 3.08 g of Oxygen .

7 0

4 years ago

The ideal gas law is a combination of all the gas laws and states that PV = nRT. The value of n stands for

dimaraw [331]

Answer:

Explanation:

p is pressure, v is vo;lume, t is temperature, r is ideal gas contstant, therefore n is the moles

7 0

3 years ago

Read 2 more answers

Find percent yield:

saveliy_v [14]

<u>Answer:</u> The percent yield of the reaction is 91.8 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

<u>For $B_5H_9$ :</u>

Given mass of $B_5H_9$ = 4.0 g

Molar mass of $B_5H_9$ = 63.12 g/mol

Putting values in equation 1, we get:

$\text{Moles of }B_5H_9=\frac{4g}{63.12g/mol}=0.0634mol$

<u>For oxygen gas:</u>

Given mass of oxygen gas = 10.0 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of oxygen gas}=\frac{10g}{32g/mol}=0.3125mol$

The chemical equation for the reaction of $B_5H_9$ and oxygen gas follows:

$2B_5H_9+12O_2\rightarrow 5B_2O_3+9H_2O$

By Stoichiometry of the reaction:

12 moles of oxygen gas reacts with 2 moles of $B_2H_5$

So, 0.3125 moles of oxygen gas will react with = $\frac{2}{12}\times 0.3125=0.052mol$ of $B_2H_5$

As, given amount of $B_2H_5$ is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

12 moles of oxygen gas produces 5 moles of $B_2O_3$

So, 0.3125 moles of oxygen gas will produce = $\frac{5}{12}\times 0.3125=0.130moles$ of water

Now, calculating the mass of $B_2O_3$ from equation 1, we get:

Molar mass of $B_2O_3$ = 69.93 g/mol

Moles of $B_2O_3$ = 0.130 moles

Putting values in equation 1, we get:

$0.130mol=\frac{\text{Mass of }B_2O_3}{69.63g/mol}\\\\\text{Mass of }B_2O_3=(0.130mol\times 69.63g/mol)=9.052g$

To calculate the percentage yield of $B_2O_3$ , we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of $B_2O_3$ = 8.32 g

Theoretical yield of $B_2O_3$ = 9.052 g

Putting values in above equation, we get:

$\%\text{ yield of }B_2O_3=\frac{8.32g}{9.052g}\times 100\\\\\% \text{yield of }B_2O_3=91.8\%$

Hence, the percent yield of the reaction is 91.8 %

6 0

4 years ago