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3 years ago

13 2. Use the bar diagram to solve the following equation: 4d + 5 = 13 d d d d 5

Mathematics

1 answer:

lidiya [134]3 years ago

6 0

D=2 is the answer if you subtract 5 and 13 which is 8 then divide the 4d by it and you get 2

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What is the volume of this cube?

Annette [7]

Answer:

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Step-by-step explanation:

8 0

2 years ago

A couch and coffee table cost a total of $1080. The cost of the couch is two times the cost of the coffee table. Find the cost o

Alborosie

Answer:

$720

$360

Step-by-step explanation:

Let the cost of couch be A and that of coffee table be B

Given couch and coffee table cost $1080

That’s

A + B = $1080

Also, the cost of couch A is 2 times the cost of coffeee table B.

That’s

A = 2B

We now have two equations

A + B = 1080

A = 2B

Now ,substitute 2B for A in the first equation .

We have

A + B = 1080

2B + B = 1080

3B = 1080

Divide both sides by 3

3B/3 = 1080/3

B = 360

The coffee table cost $360

Remember A = 2B

Therefore

A = 2 x $360

A = $720

The couch cost $720 while the coffee table cost $360

3 0

3 years ago

PLEASE HELP!

WINSTONCH [101]

Answer:

Had a problem in school like this, all you gotta dois ta

4 0

3 years ago

What is the best result for h?

Kryger [21]

Answer: First option.

Step-by-step explanation:

To solve for "h" from the given the equation $S=2\pi rh+2\pi r^2$ , you need to:

Apply the Subtraction property of equality and subtract $2\pi r^2$ to both sides of the equation.

Then you need to apply the Division property of equality and divide both sides of the equation by $2\pi r$ .

Then:

$S-2\pi r^2=2\pi rh+2\pi r^2-2\pi r^2\\\\S-2\pi r^2=2\pi rh\\\\\frac{S}{2\pi r}-\frac{2\pi r^2}{2\pi r}=\frac{2\pi rh}{2\pi r}\\\\\frac{S}{2\pi r}-r=h$

6 0

3 years ago

Read 2 more answers

Given: <br><br>EM, EQ-secants<br><br>Prove: MP·EW=WQ·EP

Dennis_Churaev [7]

Answer:

Step-by-step explanation:

A secant is a straight line from a point outside a given circle that passes through two points on its circumference.

From the given diagram, EM and EQ are secants.

Thus,

<PEW ≅ <WEP (common angles)

<EMP ≅ <EQW (secant-chord theorem)

<WMP ≅ <PQM (inscribed angles of arc WP)

Therefore,

$\frac{EW}{WM}$ = $\frac{EP}{PQ}$ (corresponding sides of a triangle)

This implies that,

EW*PQ = EP*WM

Therefore,

MP*EW = WQ*EP (properties of a similar triangle)

7 0

3 years ago