This is not correct. It is not taking into account the 150 employees.
Answer:
1) ![G(t) = 75 + \frac{23}{4}t\\](https://tex.z-dn.net/?f=G%28t%29%20%3D%2075%20%2B%20%5Cfrac%7B23%7D%7B4%7Dt%5C%5C)
2) After 8 minutes delivering fuel the tanks will have 121 gallons of fuel
Step-by-step explanation:
1) For generating the equation we have to take into account that in the tanks there is a initial volume of fuel that corresponds to 75 gallons, as it is stated that tank one is half full. As the capacity for tank 1 is of 150 gallons, half of the tank equals to:
![\frac{150}{2} = 75 gallons](https://tex.z-dn.net/?f=%5Cfrac%7B150%7D%7B2%7D%20%3D%2075%20gallons)
Now we have to convert the rate of delivery that is expressed as a mixed number to an improper fraction so:
![5\frac{3}{4} = \frac{(5x4)+3}{4} = \frac{23}{4}](https://tex.z-dn.net/?f=5%5Cfrac%7B3%7D%7B4%7D%20%3D%20%5Cfrac%7B%285x4%29%2B3%7D%7B4%7D%20%3D%20%5Cfrac%7B23%7D%7B4%7D)
Then the pumping rate is of 23/4 gallons per minute, to get how many gallons are in the tank we just need to multiply this rate by the time in minutes, and as there is an initial volume we have to add it, so we have the following equation:
![G(t) = 75 + \frac{23}{4}t\\](https://tex.z-dn.net/?f=G%28t%29%20%3D%2075%20%2B%20%5Cfrac%7B23%7D%7B4%7Dt%5C%5C)
2) To know how much fuel is in the tank after 8 minutes we have to replace this time in the previous equation so we have
![G(t) = 75 + \frac{23}{4}t\\G(8) = 75 + \frac{23}{4}(8)\\G(8) = 75 + 23(2)\\G(8) = 75 + 46\\G(8) = 121 gallons](https://tex.z-dn.net/?f=G%28t%29%20%3D%2075%20%2B%20%5Cfrac%7B23%7D%7B4%7Dt%5C%5CG%288%29%20%3D%2075%20%2B%20%5Cfrac%7B23%7D%7B4%7D%288%29%5C%5CG%288%29%20%3D%2075%20%2B%2023%282%29%5C%5CG%288%29%20%3D%2075%20%2B%2046%5C%5CG%288%29%20%3D%20121%20gallons)
After 8 minutes delivering fuel the tanks will have 121 gallons of fuel
1. Answer: Vertical shift up 3 units and vertical stretch by factor of 2
<u>Step-by-step explanation:</u>
f(x) = √x
g(x) = 2√x + 3
- adding 3 is a vertical shift up 3 units
- multiplying by 2 is a vertical stretch by factor of 2
2. Answer: Domain: [0, ∞)
Range: [3, ∞)
<u>Step-by-step explanation:</u>
g(x) = 2√x + 3
Domain: The restriction on "x" is that the radical must be greater than or equal to 0. So, x ≥ 0 Interval Notation: [0, ∞)
Range: Since the radical must be greater than or equal to 0, then 2√x is also greater than or equal to 0. Add 3 to that and y ≥ 3. Interval Notation: [3, ∞)
Answer:
5454, 5,4545
5
Step-by-step explanation:
n m
Answer:
23. 216
24. 56
25. 52
for 26, 27 i'll try to calculate the answer, sorry