<img src="https://tex.z-dn.net/?f=3x%5E3%20-%207x%5E2%20%5C%20x" id="TexFormula1" title="3x^3 - 7x^2 \ x" alt="3x^3

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lara31 [8.8K]

3 years ago

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Mathematics

1 answer:

MaRussiya [10]3 years ago

6 0

X(3x^2-7x+1)
You can only factor out a “x”

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An asset is purchased on April 1st and has an annual depreciation amount of $3,600. Using the straight-line method of depreciati

Free_Kalibri [48]

From April to December =9 months

the depreciation expense
3,600×(9÷12)=2,700

5 0

3 years ago

Read 2 more answers

Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx

shutvik [7]

$\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)$

Let $v=x+y$ , so that $\dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}$ :

$\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1$

Now the ODE is separable, and we have

$\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx$

Integrating both sides gives

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx$

For the integral on the left, rewrite the integrand as

$\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v$

Then

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C$

and so

$\csc v-\cot v=x+C$

$\csc(x+y)-\cot(x+y)=x+C$

Given that $y(0)=\dfrac\pi2$ , we find

$\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1$

so that the particular solution to this IVP is

$\csc(x+y)-\cot(x+y)=x+1$

5 0

3 years ago

James correctly answered 85% of the 60 problems on his math test. How many questions did James answer correctly❄️

harina [27]

Answer:

James answered 51 questions correctly.

Step-by-step explanation:

1) Slide the decimal 2 places to the left in the percentage (85% = .85)

2) Multiply total by new decimal (60 x .85)

3) All done! (51)

Keep in mind that 100% is just 1 whole. Therefor 85% of one whole is .85. In this problem, 60 represents our whole.

3 0

3 years ago

Help please. Will put brainliest

Murrr4er [49]

Answer:

17,750
1737

Step-by-step explanation:

A suitable table or calculator is needed.

One standard deviation from the mean includes 68.27% of the total, so the number of bottles in the range 20 ± 0.16 ounces will be ...

0.6827·26,000 = 17,750 . . . . . within 20 ± 0.16

The number below 1.5 standard deviations below the mean is about 6.68%, so for the given sample size is expected to be ...

0.66799·26,000 = 1737 . . . . . below 19.76

_____

<em>Comment on the first number</em>

The "empirical rule" tells you that 68% of the population is within 1 standard deviation (0.16 ounces) of the mean. When the number involved is expected to be expressed to 5 significant digits, your probability value needs better accuracy than that. To 6 digits, the value is 0.682689, which gives the same "rounded to the nearest integer" value as the one shown above.

4 0

3 years ago

Brennon has a summer job working for the

Lera25 [3.4K]

Brennon should make about $212.05. since 153/18 is 8.5, all we do is multiply 8.5 by 25. that gives us 212.5, convert it to money and you get $212.05.

6 0

3 years ago