Solve for x 2/3x -2= 16

Ms.wilcox bought a sofa and a chair during the sale. The regular price of the sofa was $875 and the regular price of the chair w

coldgirl [10]

Answer:

Step-by-step explanation:

474$

7 0

2 years ago

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(4x + 4) (5x + 2) =

kirill115 [55]

Answer:

Step-by-step explanation:

20x^2+28x+8

4 0

2 years ago

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Determine the intercepts of the line. y = -2x-21 X-intercept: y-intercept:

vfiekz [6]

Ummm eeee i dont knowwwe

4 0

2 years ago

(0, -9) and (-3, -3) I need this problem solved with work please!

nirvana33 [79]

Answer:

-9-(-3)/0-(-3) = -3/3 = -1

y+9= -1(x-0) Point Slope form

y+9-9= -1x-9

y= -x-9 Slope Intercept form

y+x+9 = -x-9 +x+9

y+x+9= 0 General form

4 0

3 years ago

A person purchased a slot machine and tested it by playing it 1,137 times. There are 10 different categories of outcomes, includ

ivann1987 [24]

Answer:

$p_v= P(\chi^2_{9}>11.517)=0.2419$

And on this case if we see the significance level given $\alpha=0.1$ we see that $p_v>alpha$ so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.

Step-by-step explanation:

A chi-square goodness of fit test determines if a sample data obtained fit to a specified population.

$p_v$ represent the p value for the test

O= obserbed values

E= expected values

The system of hypothesis for this case are:

Null hypothesis: $O_i = E_i[/tex[Alternative hypothesis: [tex]O_i \neq E_i$

The statistic to check the hypothesis is given by:

$\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

On this case after calculate the statistic they got: $\chi^2 = 11.517$

And in order to calculate the p value we need to find first the degrees of freedom given by:

$df=n-1=10-1=9$ , where k represent the number of levels (on this cas we have 10 categories)

And in order to calculate the p value we need to calculate the following probability:

$p_v= P(\chi^2_{9}>11.517)=0.2419$

And on this case if we see the significance level given $\alpha=0.1$ we see that $p_v>alpha$ so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.

6 0

3 years ago