Combine the two equations in the right amounts to eliminate y :
-2 (2x + 3y) + (3x + 6y) = -2 (17) + 30
-4x - 6y + 3x + 6y = -34 + 30
-x = -4
x = 4
Solve for y :
2x + 3y = 17
8 + 3y = 17
3y = 9
y = 3
12:4=3
9:3=3
so u multiply each side by 3 to get the second triangle..
answer: 4.5*3 =13.5
Answer:
1. -16-(-11)=5
2.48 divided by -8 is 12
3.13/5=2
4.81-11=7
5.3*2=35
6 35*2=5
Step-by-step explanation:
Answer:
First option and Fourth option.
Step-by-step explanation:
To solve this exercise you need to use the following Trigonometric Identity:

In this case you know that:

Since triangle ABC is similar to triangle DEF:

Let's begin with the triangle ABC.
You can identify that:

Then, substituing values, you get:

In triangle DEF, you know that:

So, substituing values, you get:

Answer:
The values of x which would give an area of 240m² would be:

Step-by-step explanation:
Given
The base of triangle b = 2x+1
The height of triangle h = 6x-3
The Area of the triangle A = 240 m²
The Area of the triangle has the formula
A = 1/2 × b × h
substituting b = 2x+1, h = 6x-3 and A = 240



Subtract 480 from both sides




Using the zero factor principle
if ab=0, then a=0 or b=0 (or both a=0 and b=0)

solving


Divide both sides by 2


also solving


Divide both sides by 2


Therefore, the values of x which would give an area of 240m² would be:
