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2 years ago

Find the derivative for the problem below and show ur work

Mathematics

1 answer:

aliya0001 [1]2 years ago

7 0

The derivative of the function is $\frac{3\left(6x+5\right)\left(3x^2+5x+1\right)^{\frac{1}{2}}}{2}$ .

<h3>What is Derivative?</h3>

The derivative is the instantaneous rate of change of a function with respect to one of its variables.

Given function:

y= (3x²+5x+1) $^{3/2}$

Differentiating and applying chain rule

= 3/2 * (3x²+5x+1) $^{1/2}$ d/dx (3x²+5x+1)

= 3/2 * (3x²+5x+1) $^{1/2}$ (6x+5)

= $\frac{3\left(6x+5\right)\left(3x^2+5x+1\right)^{\frac{1}{2}}}{2}$

Hence, the value of derivative is $\frac{3\left(6x+5\right)\left(3x^2+5x+1\right)^{\frac{1}{2}}}{2}$

Learn more about derivative here:

brainly.com/question/124529

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Draw the following triangle after a translation 4 units to the left and 4 units up

tensa zangetsu [6.8K]

Answer:

just move every corner (vertices) 4 up and 4 to the left

5 0

3 years ago

Please help me, ill mark brainliest

madam [21]

Answer: $(6,1.5)$ THE GRAPH IS ATTACHED.

Step-by-step explanation:

The Slope-Intercept form of the equation of a line is:

$y=mx+b$

Where "m" is the slope of the line and "b" is the y-intercept.

In this case, you have the first equation:

$y=-\frac{1}{2}x+4\frac{1}{2}$

You can identify that:

$m=-\frac{1}{2}\\\\b=4\frac{1}{2}$

If you convert the Mixed number to a Decimal number, you get:

$b=4+0.5=4.5$

Then, knowing the slope and the y-intercept, you can graph the line.

The second equation is:

$3x-4y=12$

Solve for "y":

$-4y=-3x+12\\\\y=\frac{3}{4}x-3$

Knowing that:

$m=\frac{3}{4}\\\\b=-3$

You can graph the line.

The point of intersection between both lines, is the solution of the system. This is:

$(6,1.5)$

Observe the graph attached.

4 0

3 years ago

Which of the following is a factor of f(x)=5x^3+24x^2-75x+14

qwelly [4]

I find it convenient to let a graphing calculator help me with factoring. It shows the roots to be -7, 1/5, 2. Hence the factorization will be
.. = (x +7)(5x -1)(x -2)

4 0

3 years ago

Marcie bought a total of 20 used books and cds during a yard sale for a total of 54.50$. of books cost 1.50$ each and cds 5$ eac

melomori [17]

Let numbers of books be 'b' and numbers of CDs be 'c'

We can set up two equations:
Equation [1] ⇒ $b+c=20$
Equation [2] ⇒ $1.50b+5c=54.50$

We are solving for the number of books and the number of CDs bought

When we have two equations in terms of two different variables; $b$ and $c$ , that we need to solve, then this becomes a simultaneous equation problem.

First, rearrange Equation [1] to make either $b$ or $c$ the subject:
$b+c=20$
$b=20-c$

Then we substitute $b=20-c$ into Equation [2]
$1.50b+5c=54.50$
$1.50(20-c)+5c=54.50$
$30-1.50c+5c=54.50$
$5c-1.5c=54.50-30$
$3.5c=24.50$
$c=7$

Now we know the value of $c$ which is $c=7$ , substitute this value into $b=20-c$ we have $b=20-7=13$

Answer:
Numbers of books = 13
Numbers of CDs = 7

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4 years ago

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4 years ago