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Valentin [98]
2 years ago
8

Find the derivative for the problem below and show ur work

Mathematics
1 answer:
aliya0001 [1]2 years ago
7 0

The derivative of the function is  \frac{3\left(6x+5\right)\left(3x^2+5x+1\right)^{\frac{1}{2}}}{2}.

<h3>What is Derivative?</h3>

The derivative is the instantaneous rate of change of a function with respect to one of its variables.

Given function:

y= (3x²+5x+1)^{3/2}

Differentiating and applying chain rule

= 3/2 * (3x²+5x+1)^{1/2} d/dx (3x²+5x+1)

= 3/2 * (3x²+5x+1)^{1/2}  (6x+5)

= \frac{3\left(6x+5\right)\left(3x^2+5x+1\right)^{\frac{1}{2}}}{2}

Hence, the value of derivative is  \frac{3\left(6x+5\right)\left(3x^2+5x+1\right)^{\frac{1}{2}}}{2}

Learn more about derivative here:

brainly.com/question/124529

#SPJ1

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Draw the following triangle after a translation 4 units to the left and 4 units up
tensa zangetsu [6.8K]

Answer:

just move every corner (vertices) 4 up and 4 to the left

5 0
3 years ago
Please help me, ill mark brainliest
madam [21]

Answer:  (6,1.5)  THE GRAPH IS ATTACHED.

Step-by-step explanation:

The Slope-Intercept form of the equation of a line is:

y=mx+b

Where "m" is the slope of the line and "b" is the y-intercept.

In this case, you have the first equation:

y=-\frac{1}{2}x+4\frac{1}{2}

You can identify that:

m=-\frac{1}{2}\\\\b=4\frac{1}{2}

If you convert the Mixed number to a Decimal number, you get:

b=4+0.5=4.5

Then, knowing the slope and the y-intercept, you can graph the line.

The second equation is:

3x-4y=12

Solve for "y":

-4y=-3x+12\\\\y=\frac{3}{4}x-3

Knowing that:

m=\frac{3}{4}\\\\b=-3

You can graph the line.

The point of intersection between both lines, is the solution of the system. This is:

(6,1.5)

Observe the graph attached.

4 0
3 years ago
Which of the following is a factor of f(x)=5x^3+24x^2-75x+14
qwelly [4]
I find it convenient to let a graphing calculator help me with factoring. It shows the roots to be -7, 1/5, 2. Hence the factorization will be
.. = (x +7)(5x -1)(x -2)

4 0
3 years ago
Marcie bought a total of 20 used books and cds during a yard sale for a total of 54.50$. of books cost 1.50$ each and cds 5$ eac
melomori [17]
Let numbers of books be 'b' and numbers of CDs be 'c'

We can set up two equations:
Equation [1] ⇒ b+c=20
Equation [2] ⇒ 1.50b+5c=54.50

We are solving for the number of books and the number of CDs bought

When we have two equations in terms of two different variables; b and c, that we need to solve, then this becomes a simultaneous equation problem. 

First, rearrange Equation [1] to make either b or c the subject:
b+c=20
b=20-c

Then we substitute b=20-c into Equation [2]
1.50b+5c=54.50
1.50(20-c)+5c=54.50
30-1.50c+5c=54.50
5c-1.5c=54.50-30
3.5c=24.50
c=7

Now we know the value of c which is c=7, substitute this value into b=20-c we have b=20-7=13

Answer:
Numbers of books = 13
Numbers of CDs = 7
5 0
4 years ago
I need help with measurements
Scrat [10]
How would you like to be helped?
4 0
4 years ago
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