3 years ago

I NEED HELP ASAP DUE MORNING AND REPORT CONFERENCE TMM

Mathematics

1 answer:

Savatey [412]3 years ago

8 0

Answer:

A. Horizontal and slope is 0

B. Horizontal and slope is 0

C. Vertical and slope is undefined

D. Vertical and slope is undefined

Step-by-step explanation:

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In 2013, the Pew Research Foundation reported that "45% of U.S. adults report that they live with one or more chronic conditions

marshall27 [118]

<h2>Answer with explanation:</h2>

Formula to find the confidence interval for population proportion (p) is given by :-

$\hat{p}\pm z^* SE$

, where z* = Critical value.

$\hat{p}$ = Sample proportion.

SE= Standard error.

Let p be the true population proportionof U.S. adults who live with one or more chronic conditions.

As per given , we have

$\hat{p}=0.45$

SE=0.012

By z-table , the critical value for 95% confidence interval : z* = 1.96

Now , a 95% confidence interval for the proportion of U.S. adults who live with one or more chronic conditions.:

$0.45\pm (1.96) (0.012)$

$0.45\pm (0.02352)$

$=(0.45-0.02352,\ 0.45+0.02352)=(0.42648,\ 0.47352)$

Hence, a 95% confidence interval for the proportion of U.S. adults who live with one or more chronic conditions. $=(0.42648,\ 0.47352)$

Interpretation : Pew Research Foundation can be 95% confident that the true population proportion (p) of U.S. adults who live with one or more chronic conditions lies between 0.42648 and 0.47352 .

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Answer:

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Step-by-step explanation:

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