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3 years ago

13

Identify the domain and range of the graph.

1 answer:

Bad White [126]3 years ago

5 0

Answer:

Domain (x): (-∞ , -1) ∪ (-1 , 3) ∪ (3 , ∞)

Range (y): (3 , ∞) ∪ (-∞ , ∞) ∪ (-∞ , 3) -> (-∞ , ∞)

Step-by-step explanation:

Domain (x): (-∞ , -1) ∪ (-1 , 3) ∪ (3 , ∞)

Range (y): (3 , ∞) ∪ (-∞ , ∞) ∪ (-∞ , 3) -> (-∞ , ∞)

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Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

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3 years ago

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What's the quotient and remainder for 52÷8

ArbitrLikvidat [17]

6 r4
6 reminder 4
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~~~~~~~~~

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3 years ago

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A line is defined by the equation y=2/3x-6. The line passes through a point whose y-coordinate is 0. What is the x- coordinate o

NISA [10]

Answer: Its 9

Thats the answer

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3 years ago

An assistant cook peeled 18 potatoes in 6 minutes. At this rate, how many potatoes can he peel in 50 minutes?

malfutka [58]

Answer:

$150$ potatoes

Step-by-step explanation:

Since the assistant can peel $18$ potatoes in $6$ minutes, we know that he can peel $\frac{18}{6}=3$ potatoes in $1$ minute. Therefore, he will be able to peel $3*50=150$ potatoes in $50$ minutes. Hope this helps!

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3 years ago

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Determine whether each sum, difference, product,

PIT_PIT [208]

Answer:

28. The difference represents an irrational number

29. The difference represents a rational number

30. The quotient represents a rational number

31. The quotient represents an irrational number

Step-by-step explanation:

* Lets explain how to solve the problem

- The rational number is any numbers can be put in the form of a/b,

where a and b are integers b ≠ 0

- Ex: 1 , 2/3 , 5/4 , 22/7 , 100 , ................

- The irrational number is any number that is not rational

- It is a number that cannot be written as a ratio of two integers

or cannot be expressed as a fraction

- Ex: √2 , √7 , π , ..... (π is irrational because it's approximated value)

- If the part of the the number is irrational, then the number

is irrational

- Ex: (5 + √3) , (√7 + 5) , 2√5 , √11/4 , 5/√13

* Lets solve the problems

28. $\frac{6}{23}-\frac{\sqrt{2}}{2}$

∵ √2/2 is an irrational number

∵ One term is an irrational number

∴ The difference represents an irrational number

29. $\frac{6}{23}-\frac{15}{127}$

∵ The two terms are rational numbers

∴ The difference represents a rational number

30. $\frac{6}{23}$ ÷ $\frac{15}{127}$

∵ The two terms are rational numbers

∴ The quotient represents a rational number

31. $\frac{6}{23}$ ÷ $\frac{\sqrt{2}}{2}$

∵ √2/2 is an irrational number

∵ One term is an irrational number

∴ The quotient represents an irrational number

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4 years ago